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FrozenT [24]
3 years ago
15

Select the correct answer.

Physics
2 answers:
viva [34]3 years ago
8 0
The correct answer is B
natali 33 [55]3 years ago
4 0

The wave speed completely depends on the characteristics and properties of the medium  . . . physical properties for mechanical waves, electrical properties for electromagnedtic waves.

So if you want to change the speed of a wave, you have to change the medium . . . shoot it through some different kind of stuff. <em>(B) </em>

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ASAP!!! A cell phone charger supplies 2.0A of current to your phone. you plug in your phone overnight (8 hours). how much charge
Ksivusya [100]

current = charges / times (sec)

if a current of 2A flows for 8 hours(28800sec), then 2 * 28800 = 57600 coulombs of electrical charge move through the phone

6 0
4 years ago
The Earth's Radius is 6.3710x106 m and mass is 5.9742x1024 kg. What is the acceleration due to gravity at Mount Everest (elevati
Shalnov [3]

Answer is

9.773m/s^2

-----------------------------------------------------------------------------

Given,

h=8848m

The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.

g′=g(1 − 2h/h)

=9.8(1 - 6400000/17696)

=9.8(1 − 0.00276)

9.8×0.99724

=9.773m/s^2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s^2

-----------------------------------------------------------------------

hope this helps :)

3 0
3 years ago
A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i
RideAnS [48]

answer

6000 N

explanation

every force has an equal and opposite reaction force, so the force exerted by the truck on the car is the same as the force exerted by the car on truck

the force is 6000 N

8 0
4 years ago
Read 2 more answers
A smooth circular hoop with a radius of 0.400 m is placed flat on the floor. A 0.325-kg particle slides around the inside edge o
aleksandrvk [35]

Answer:

a)  W = - 6.825 J,  b) θ = 1.72 revolution

Explanation:

a) In this exercise the work of the friction force is negative and is equal to the variation of the kinetic energy of the particle

         W = ΔK

         W = K_f - K₀

          W = ½ m v_f² - ½ m v₀²

         W = ½ 0.325 (5.5² - 8.5²)

         W = - 6.825 J

b) find us the coefficient of friction

Let's use Newton's second law

            fr = μ N

y-axis (vertical)   N-W = 0

            fr = μ W

work is defined by

             W = F d

the distance traveled in a revolution is

             d₀ = 2π r

             W = μ mg d₀ = -6.825

            μ = \frac{ -6.825}{d_o \ mg}

               

The total work as the object stops the final velocity is zero v_f = 0

         W = 0 - ½ m v₀²

          W = - ½ 0.325 8.5²

          W = - 11.74 J

           μ mg d = -11.74

           

we subtitle the friction coefficient value

           ( \frac{-6.8525 }{d_o mg}) m g d = -11.74

               6.825  \frac{d}{d_o} = 11.74

               d = 11.74/6.825  d₀

               d = 1.7201  2π 0.400

               d = 4.32 m

this is the total distance traveled, the distance and the angle are related

              θ = d / r

              θ = 4.32 / 0.40

              θ = 10.808 rad

we reduce to revolutions

              θ = 10.808 rad (1rev / 2π rad)

              θ = 1.72 revolution

3 0
3 years ago
How to find the frictional force acting on an object (not the friction coefficient)? ...?
Dovator [93]
One can simply find the frictional force acting on an object using this equation:

 (Ffrict<span> = μ•F</span>norm<span>)
</span>

The process of determining the value of the individual forces acting upon an object involve an application of Newton's second law (Fnet=m•a) and an application of the meaning of the net force. If mass (m) and acceleration (a) are known, then the net force (Fnet) can be determined by use of the equation.

<span>Fnet = m • a</span>

If the numerical value for the net force and the direction of the net force is known, then the value of all individual forces can be determined.

7 0
3 years ago
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