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masya89 [10]
4 years ago
15

How does the shape and size of the continents today help support the Theory of Continental Drift?

Physics
1 answer:
astraxan [27]4 years ago
4 0

The size and shape of the continents help support the continental drift because they all most fit together like puzzle pieces
You might be interested in
Q2. You push a crate up a ramp with a force of 10 N. Despite your pushing, the crate slides down the ramp 4 m. How much work did
Ksivusya [100]

Answer:

40 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Work done is simply defined as the product of force and distance moved in the direction of the force. Mathematically, we can express the Workdone as:

Workdone = force × distance

Wd = F × s

With the above formula, we can obtain the workdone as follow:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Wd = F × s

Wd = 10 × 4

Wd = 40 J

Thus, 40 J of work was done.

5 0
3 years ago
In a wave, what do you call the difference from crest to crest or trough to trough
UNO [17]
The correct answer is "wavelength".

In fact, this is exactly the definition of wavelength: in a wave, the wavelength is defined as the distance between two succesive crests or two successive troughs, therefore the correct answer is 
D) wavelength.
7 0
3 years ago
A constant force of 5KN pulls a crate along a distance of 15 m in 75s.What is the power​
xxMikexx [17]

Explanation:

We know,

1KN = 1000N

Then, Force(F) = 5*1000N

=5000N

Here,

Power (P)=Work(W)/Time(T)

=Force * distance/ Time (W = F*s)

= 5000*15/75

=1000

So, The power of body or object is 1000Watt.

I hope this will be helpful for you.

8 0
4 years ago
If the moon is rising at midnight, the phase of the moon must be
Nadya [2.5K]
The phase is called 3rd quarter.

Hope this helps:)
7 0
3 years ago
In an insulated cup of negligible heat capacity, 50. G of water at 40. °c is mixed with 30. G of water at 20. °c. The final temp
Tatiana [17]

The final temperature of the mixture is closest to 32.5 °C

<h3>Data obtained from the question</h3>
  • Mass of warm water (Mᵥᵥ) = 50 g
  • Temperature warm water (Tᵥᵥ) = 40 °C
  • Mass of cold water (M꜀) = 30 g
  • Temperature of cold water (T꜀) = 20 °C
  • Specific heat capacity of the water = 4.184 J/gºC
  • Equilibrium temperature (Tₑ) =?

<h3>How to determine the equilibrium temperature </h3>

Heat loss = Heat gain

MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – M꜀)

50 × 4.184 (40 – Tₑ) = 30 × 4.184(Tₑ – 20)

209.2(40 – Tₑ) = 125.52(Tₑ – 20)

Clear bracket

8368 – 209.2Tₑ = 125.52Tₑ – 2510.4

Collect like terms

8368 + 2510.4 = 125.52Tₑ + 209.2Tₑ

10878.4 = 334.72Tₑ

Divide both side by 334.72

Tₑ = 10878.4 / 334.72

Tₑ = 32.5 °C

Learn more about heat transfer:

brainly.com/question/6363778

6 0
2 years ago
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