Answer:
![E = 3.88 * 10^{-17} J](https://tex.z-dn.net/?f=E%20%3D%203.88%20%2A%2010%5E%7B-17%7D%20J)
Explanation:
Energy is directly proportional to frequency and it is given as:
E = hf
where h = Planck's constant
f = frequency
To get frequency, we use the formula of speed:
c = λf
where c = speed of light
λ = wavelength
=> f = c/λ
Therefore, the energy of the photon will be:
E = hc/λ
![E = \frac{6.626 * 10^{-34} * 3 * 10^{8} }{512 * 10^{-9} }](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B6.626%20%2A%2010%5E%7B-34%7D%20%2A%203%20%2A%2010%5E%7B8%7D%20%20%7D%7B512%20%2A%2010%5E%7B-9%7D%20%7D)
![E = 3.88 * 10^{-17} J](https://tex.z-dn.net/?f=E%20%3D%203.88%20%2A%2010%5E%7B-17%7D%20J)
The energy of the photon is ![3.88 * 10^{-17} J](https://tex.z-dn.net/?f=3.88%20%2A%2010%5E%7B-17%7D%20J)
Answer:
1840:1
Explanation:
If m is the mass of the electron, and 1840m is the mass of the proton, then:
p₁ = p₂
m₁v₁ = m₂v₂
m v₁ = 1840m v₂
v₁ = 1840 v₂
The kinetic energy of the electron is:
KE₁ = ½ m₁ v₁²
KE₁ = ½ m (1840 v)²
KE₁ = 1692800 mv²
The kinetic energy of the proton is:
KE₂ = ½ m₂ v₂²
KE₂ = ½ (1840m) v₂²
KE₂ = 920 mv²
The ratio of the kinetic energies is:
KE₁ / KE₂
(1692800 mv²) / (920 mv²)
1840:1
Answer:
Explanation:
In equilibrium , weight of mug is equal to restoring force .
mg = kx where m is mass of mug , k is spring constant and x is extension .
k / m = g / x = 9.8 ms⁻² / .025 m
= 392
frequency of oscillation n = ![\frac{1}{2\pi}\sqrt{\frac{k}{m} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5Cpi%7D%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%20%7D)
![n=\frac{1}{2\pi}\sqrt{392 }](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B1%7D%7B2%5Cpi%7D%5Csqrt%7B392%20%7D)
= 4.46 per second.
Due to friction from sliding against the ground, the player decelerates in 1 direction. Thus his momentum decreases.
Answer:
Input force is the initial force used to get a machine to begin working. Machines are designed to increase the input force for a larger output force. The quality of a machine is measured by mechanical advantage. The mechanical advantage is the ratio of the output force to the input force.
Explanation: