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disa [49]
3 years ago
13

How can an abiotic factor affect a biotic factor

Chemistry
1 answer:
xenn [34]3 years ago
4 0
Biotic and abiotic factors are the environmental conditions that the organisms have to face to live in a specified environment.

-Abiotic factors-
Abiotic factors are the physical and chemical conditions of an environment. For example : heat, salinity, pressure, light, wind, pH ...

-Biotic factors-
Biotic factors are all the biological conditions of an environment for a specie/taxa. It can include prey and predator abundance, available food amount, available space, intra and interspecific competition...

The development of organims is under the control of abiotic factors. Some are adapted to heat, cold etc ... The abiotic factors will define which organisms are able or not to live in a specified place.

The living organisms will constitute the biotic factors, which define if and how can an organism live in a specified environment.
So, the abiotic factors are controling the biotic factors of an environment.

Hope it helps you !
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9. If the limits of cow hearing are 23 Hz to 35,000 Hz, what are the sound wavelengths that are
hammer [34]

Answer:

wave length=speed/frequency

=365/23

wave length=speed/frequency

=365/35000

3 0
3 years ago
Lily replicates an experiment that found that the number of calories in a particular food is 50 kcal. She obtained data from
Tresset [83]

Answer:

invalid

Explanation:

Just imagine doing this experiment MULTIPLE TIMES and one of the trials you get 72 Kcal while in another u get 12kcal. It doesn't make sense. Somewhere in the experiment she went wrong. So its invalid

4 0
4 years ago
What does a steep air pressure gradient cause? A. variable winds B. light winds C. high winds D. north winds
ZanzabumX [31]
The answer is 'C' high winds.
4 0
3 years ago
Read 2 more answers
10.0 g of gaseous ammonia and 6.50 g of oxygen gas are introduced into a previously evacuated 5.50 L vessel. If the ammonia and
Shalnov [3]

Answer:

The density is 3g/L

Explanation:

The reaction that occurs in the vessel is:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

10,0g of NH₃ are:

10,0g * \frac{1mol}{17,031g} = 0,587 moles

6,50 g of O₂ are:

6,50g * \frac{1mol}{32g} = 0,203 moles

For a complete reaction of O₂ there are necessaries:

0,203 mol * \frac{4molNH_{3}}{5molO_{2}}= 0,163 moles of NH_{3}

O₂ is limiting reactant. The excess moles of NH₃ are:

0,587 - 0,163 = <em>0,424 moles of NH₃</em>

These moles are:

0,424mol * \frac{17,031g}{1mol} = <em>7,22g of NH₃</em>

Knowing O₂ is limiting reactant, mass of NO and H₂O are:

0,203molO_{2}*\frac{4molNO}{5molO_{2}}*\frac{30,01g}{1molNO} = <em>4,87g of NO</em>

0,203molO_{2}*\frac{6molH_{2}O}{5molO_{2}}*\frac{18,02g}{1molH_{2}O} = <em>4,39g of H₂O</em>

The total mass is: 7,22g + 4,87g + 4,39g = 16,48g ≡ <em>16,5g </em>

<em>-</em><em>The same mass add in the first. By matter conservation law-</em>

As vessel volume is 5,50L, density is:

16,5g/5,50L = <em>3g/L</em>

I hope it helps!

7 0
4 years ago
Please help!
Alchen [17]
After crossbreeding, the seeds will be in the form below
Rr, Rr, rr and rr
which is two for each in four possible outcomes bringing the ratio to 1:1
which is equivalent to 1/2
so 1/2 as a percentage is
=1/2*100
=50%
8 0
3 years ago
Read 2 more answers
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