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hichkok12 [17]
3 years ago
15

When does a metal atom stop reacting

Physics
2 answers:
Naily [24]3 years ago
5 0

Answer:

When a metal element reacts with a non-metal element an ionic compound is formed. An understanding of the way the elements are bonded allows us to explain their typical properties.

Reactions between metals and non-metals include:

sodium + chlorine → sodium chloride

magnesium + oxygen → magnesium oxide

calcium + chlorine → calcium chloride

Explanation:

In all of these reactions, the metal atoms give electrons to the non-metal atoms. The metal atoms become positive ions and the non-metal atoms become negative ions.

Lunna [17]3 years ago
3 0

Answer:

When metals react with non-metals

Explanation:

When metals react with non-metals, electrons are transferred from the metal atoms to the non-metal atoms, forming ions. The resulting compound is called an ionic compound. Reactions between metals and non-metals include: sodium + chlorine → sodium chloride.

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What happens to a circuit's resistance (R), voltage (V), and current (1) when
hammer [34]

Answer:

D.

R increases

V is constant

I decreases

Explanation:

The resistance of a wire is given by the following formula:

R = \frac{(Resistivity)(L)}{A}

It is clear from this formula that resistance is directly proportional to the length of wire. So, when length of wire is increased, <u>the resistance of circuit increases</u>.

The <u>voltage in the circuit will be constant</u> as the voltage source remains same and it is not changed.

Now, we can use Ohm Law:

V = IR

at constant V:

I ∝ 1/R

it means that current is inversely proportional to resistance. Hence, the increase of resistance causes <u>the current in circuit to decrease.</u>

Therefore, the correct option will be:

<u>D.</u>

<u>R increases </u>

<u>V is constant </u>

<u>I decreases</u>

6 0
3 years ago
Determine the CM of the uniform thin L-shaped construction brace shown in (Figure 1) . Suppose that a = 2.20 m and b = 1.63 m De
aleksandrvk [35]

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is \bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}} meters.

<h3>How to determine the coordinates of the center of mass of a compound figure </h3>

Let suppose that the entire construction has a <em>uniform</em> mass, then the coordinates of the center of mass can be determined by definition of <em>weighted</em> average:

\bar x = \frac{\sum \limits_{i = 1}^{n}x_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}     (1)

\bar y = \frac{\sum \limits_{i = 1}^{n}y_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}     (2)

If we know that a = 2.20 m and b = 1.63 m, then the x-coordinates of the center of mass of the compound figure is:

\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is \bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}} meters.

To learn more on center of mass: brainly.com/question/8662931

#SPJ1

8 0
2 years ago
When it comes to temperature maps, winds will from high temps to cold or cold temps to warm.
iragen [17]
Cold to warm is the correct answer.
3 0
3 years ago
In the equation for the gravitational force between two objects, which quantity must be syuu
Anton [14]

Answer:

it is    F = G(m1)(m2)/d^2

Explanation:

lol you take ed genuity too

6 0
3 years ago
A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. The total energy
m_a_m_a [10]

Answer:

(A) Spring constant will be 126.58 N/m

(B) Amplitude will be equal to 0.177 m

Explanation:

We have given mass of the block m = 200 gram = 0.2 kg

Time period T = 0.250 sec

Total energy is given TE = 2 J

(A) For mass spring system time period is equal to T=2\pi \sqrt{\frac{m}{K}}

So 0.250=2\times 3.14 \sqrt{\frac{0.2}{K}}

0.0398=\sqrt{\frac{0.2}{K}}

Now squaring both side

0.00158=\frac{0.2}{K}

K = 126.58 N/m

So the spring constant of the spring will be 126.58 N/m

(B) Total energy is equal to TE=\frac{1}{2}KA^2, here K is spring constant and A is amplitude

So 2=\frac{1}{2}\times 126.58\times A^2

A^2=0.0316

A = 0.177 m

So the amplitude of the wave will be equal to 0.177 m

6 0
3 years ago
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