Answer:
B => Mg° => Mg⁺² + 2e⁻
Explanation:
2Mg° + O₂ => 2MgO rewrite => Mg° + 1/2O₂ => 2MgO
Oxidation Half Rxn => Mg° => Mg⁺² + 2e⁻
Reduction Half Rxn => 1/2O₂ + 2e⁻ => 2O⁻
__________________________________-
FYI Note => For half-reactions one always finds the electrons listed on the product side of the reaction for oxidation reactions and for reduction reactions on the reactant side.
Your answer is A mixed with.
The nucleus of an atom contain neutrons and protons, and energy levels surround the nucleus, in rings and contain electrons
N₂H₄ + 2H₂O₂ → N₂ + 4H₂O
mol = mass ÷ molar mass
If mass of hydrazine (N₂H₄) = 5.29 g
then mol of hydrazine = 5.29 g ÷ ((14 ×2) + (1 × 4))
= 0.165 mol
mole ratio of hydrazine to Nitogen is 1 : 1
∴ if moles of hydrazine = 0.165 mol
then moles of nitrogen = 0.165 mol
Mass = mol × molar mass
Since mol of nitrogen (N₂) = 0.165
then mass of hydrazine = 0.165 × (14 × 2)
= 4.62 g
