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ruslelena [56]
3 years ago
12

Compound A has molecular formula C5H11Br. When compound A is treated with bromine in the presence of UV light, the major product

is 2,2-dibromopentane. Treatment of compound A with NaSH (a strong nucleophile) produces a compound with one chirality center having the R configuration. What is the structure of compound A

Chemistry
1 answer:
damaskus [11]3 years ago
6 0

The compound (A) is 2-bromo-pentane. See attached picture for the chemical diagram.

Explanation:

2-bromo-pentane (A) reacts with bromine (Br₂) under UV light to form 2,2-dibromopentane and HBr. Also 2-bromo-pentane (A) reacts with NaSH to from pentane-2-thiol, which have an asimetric carbon, and NaBr.

You may find the chemical reactions and diagrams of the compounds in the attached picture.

Learn more about:

structure of organic compounds

brainly.com/question/9315917

brainly.com/question/13794915

#learnwithBrainly

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igomit [66]

Answer:

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Explanation:

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6 0
3 years ago
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How many grams of H2O would be made from 7.9 moles of H2? (Round to one decimal place)
Paraphin [41]

Answer:

2.01588 grams

Explanation:

4 0
3 years ago
Excess Ca(OH)2 is shaken with water to produce a saturated solution. The solution is filtered, and a 50.00 mL sample titrated wi
julia-pushkina [17]

<u>Answer:</u> The K_{sp} for calcium hydroxide is 5.324\times 10^{-6}

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.0983M\\V_1=11.22mL\\n_2=2\\M_2=?M\\V_2=50mL

Putting values in above equation, we get:

1\times 0.0983\times 11.22=2\times M_2\times 50\\\\M_2=0.011M

The concentration of Ca(OH)_2 comes out to be 0.011 M.

The balanced equilibrium reaction for the ionization of calcium hydroxide follows:

Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-

The expression for solubility constant for this reaction follows:

K_{sp}=[Ca^{2+}][OH^-]^2

Putting the values in above equation, we get:

K_{sp}=(0.011)\times (2\times 0.11)^2

K_{sp}=5.324\times 10^{-6}

Hence, the K_{sp} for calcium hydroxide is 5.324\times 10^{-6}

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3 years ago
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When HCl is added to a saturated solution of PbCl2, the solubility of PbCl2 would decrease so precipitation would occur. The decrease in the solubility is due to the common ion effect or the presence of Cl- ions in both compounds.
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