Answer:
Mole fraction for benzene is 0.683
Explanation:
We need to determine the colligative property about vapour pressure which formula is:
ΔP = P° . Xm
where P° is vapour pressure of pure solvent.
ΔP = Vapor pressure of pure solvent - Vapor pressure of solution
In this case, our solvent is benzene and the solute is toluene. For this colligative property vapour pressure of solution is lower than pure solvent.
P° of benzene at 20°C is 74.7 Torr
Xm is the value for the mole fraction of solute.
Let's replace data: 74.7 Torr - 51 Torr = 74.7 Torr . Xm
Xm = 0.317 → That's the mole fraction for toluene.
Then, mole fraction for benzene will be: 1 - 0.317 → 0.683
Answer:

Explanation:
Hello,
In this case, with the given chemical reaction:

We can notice a 1:1 mole ratio between hydrogen gas and beryllium metal, therefore, beryllium requirement is computed as shown below:

Regards.
Answer:
.Competitive inhibition occurs when a O A. substrate binds to an enzyme in the active site and activates the enzyme B. molecule binds to an enzyme in the active site and prevents the substrate from binding C. molecule binds to an enzyme at a site other than the active site and inhibits the substrate from binding O D. molecule binds to an enzyme but doesn't change the shape of the active site Mark for review (Will be highlighted on the review page) << Previous Question Next Question >>
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