Answer:
The correct answer -
a. Cd and Pb(NO3)2
b. Redox reactions
c. Pb and Cd(NO3)2
Explanation:
This is the reaction known as the redox or reduction-oxidation reaction of metals. In this particular reaction, there are two reactants Cadmium (III) in solid-state and lead (II) nitrate in the aqueous state. At the end of this reaction, the products that we get are lead (II) in solid-state and Cadmium (III) nitrate in the aqueous state.
cadmium (s)+ lead nitrate (aq) = lead (s) + cadmium nitrate (aq)
Cd (s) + Pb2+(aq) → Pb(s) + Cd2+(aq)
Here, Oxidizing agent is Pb2+ and the reducing agent is Cd.
Answer:
1 x 10^13 stadiums
Explanation:
We are given that;
1 stadium holds = 1 × 10^5 people
Number of iron atoms is 1 × 10^18 atoms
Assuming the stadium would carry an equivalent number of atoms as people.
Then, 1 stadium will carry 1 × 10^5 atoms
Therefore,
To calculate the number of stadiums that can hold 1 × 10^18 atoms we divide the total number of atoms by the number of atoms per stadium. Number of stadiums = Total number of atoms ÷ Number of atoms per stadium
= 1 × 10^18
atoms ÷ 1 × 10^5 atoms/stadium =
1 × 10^13 Stadiums
Thus, 1 × 10^18 atoms would occupy 1 × 10^13 stadiums
Whats the question?!?! You never put the question.
Gold, as it has the unique characteristic yo