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Mkey [24]
2 years ago
10

Can someone pls help me?

Chemistry
1 answer:
kolbaska11 [484]2 years ago
7 0

Answer:

17

Explanation:

what is the independent variable

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A 200.0 mL solution of 0.40 M ammonium chloride was titrated with 0.80 M sodium hydroxide. What was the pH of the solution after
choli [55]

Answer:

9.25

Explanation:

Let first find the moles of NH_4Cl and NaOH

number of moles of NH_4Cl = 0.40  mol/L × 200 ×  10⁻³L

= 0.08 mole

number of moles of NaOH = 0.80  mol/L × 50 ×  10⁻³L

= 0.04 mole

The equation for the reaction is expressed as:

NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

The ICE Table is shown below as follows:

                            NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

Initial (M)              0.08            0.04                            0

Change (M)         - 0.04          -0.04                          + 0.04

Equilibrium (M)      0.04             0                                0.04

K_a*K_b = 10^{-14} \ at \ 25^0C

K_a = \frac{10^{-14}}{K_b}

K_a = \frac{10^{-14}}{1.76*10^{-5}}

K_a= 5.68*10^{10}

pK_a = - log \ (K_a)

pK_a = - log \ (5.68*10^{-10})

pK_a = 9.25

pH = pKa + \ log (\frac{HB}{HA} )   for buffer solutions

pH = pKa + \ log (\frac{moles \ of \ base }{ moles\ of \ acid} ) since they are in the same solution

pH = 9.25 + \ log (\frac{0.04 }{ 0.04} )

pH = 9.25

8 0
2 years ago
The rotational period of the moon is_____
Ivahew [28]

Answer:

Hi, I think the D since the moon rotates about once a month and these months have different amounts of days. an example would be February that can have like 28 or 29 in leap year

Explanation:

6 0
3 years ago
Is the osmosis egg challenge a chemical reaction?
Vikki [24]

Answer:

Answer is C because in exothermic reactions, energy releases.

in Cellular respiration,

ATP+H20 (water) = ADP+ Pi + Energy

So celullar respiration is exothermic and releases energy

6 0
3 years ago
Read 2 more answers
A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade​
egoroff_w [7]

Answer:

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

Explanation:

Assuming Pressure is constant.

\frac{V_1}{T_1} = \frac{V_2}{T_2}

where T1 and T2 are temperature in Kelvin

Substituting the give values we get-

\frac{300}{273} = \frac{V_2}{288}

V_2 = \frac{288*300}{273} \\V_2 = 316.5

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

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2 years ago
What is the ending of the electron configuration of each element in group 4?
bogdanovich [222]
<span>because p6 will be the group 8. You have to count the 2 electrons from the "s" block that are Group I and Group II Group I s1 Group II s2 Group III s2 p1 Group IV s2 p2 Group V s2 p3 Group VI s2 p4 Group VII s2 p5 Group VIII s2 p6</span>
6 0
3 years ago
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