Answer:
The observer detects light of wavelength is 115 nm.
(b) is correct option
Explanation:
Given that,
Wavelength of source = 500 nm
Velocity = 0.90 c
We need to calculate the wavelength of observer
Using Doppler effect

Where, 


Hence, The observer detects light of wavelength is 115 nm.
Answer:
Volume charge density: When the charge density is throughout the volume of a body, then the charge per unit volume is called volume charge density and it is represented by ρ.
∴ρ=

Hence the unit of ρ is Cm
−3
Example: If a charge q is uniformly distributed in the whole volume of a
sphere of radius R, then p =
=3q/4πR-3
The answer would be: c. High levels of dissolved oxygen
Oxygen is vital for most (aerobic) organism. Fish using oxygen that dissolved in the water so high level of dissolved oxygen will make the fish grow easier. Water with pH of 5 would be an acid water. Acid is corrosive and it can kill some organism that sensitive. High levels of fecal coliform mean the water contaminated with fecal material and must have a high level of bacteria.
Based on the given values above, in order for us to get the answer, we need to convert the units first. So in 1 kilogram, there is 1,000,000 micrograms. In this case, 1.6 kilograms is 1,600,000 micrograms. For the week to seconds, 1 week is equivalent to 604,800 seconds. Therefore, 1,600,000 micrograms/604,800 seconds. So we are going to simplify this. So it would be 2.65<span>µg/s. Hope this answers your question.</span>
Answer:
(a) λ = 4136 nm → infrared
(b) λ = 413.6 nm → visible light
(c) λ = 41.36 nm → ultraviolet
Explanation:
The wavelength of infrared is on the range of 700 nm to 1000000 nm
The wavelength of visible light is between 400 nm and 700 nm
The wavelength of ultraviolet ray on the range of 10 nm to 400 nm
The wavelength of photon is given by;
E = hf
f is the frequency of the wave = c / λ

Where;
c is the speed of light = 3 x 10⁸ m/s
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
(a) 0.3 eV = 0.3 x 1.602 x 10⁻¹⁹ J

λ = 4136 x 10⁻⁹ m
λ = 4136 nm → infrared
(b) 3.0 eV

λ = 413.6 x 10⁻⁹ m
λ = 413.6 nm →visible light
(c) 30 eV

λ = 41.36 x 10⁻⁹ m
λ = 41.36 nm →ultraviolet