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mart [117]
3 years ago
10

HELP as shown in the diagram, points p,q, and r are located near a positively charged object.

Physics
1 answer:
tester [92]3 years ago
6 0
I can’t open or look at the image
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A source at rest emits light of wavelength 500 nm. When it is moving at 0.90c toward an observer, the observer detects light of
Vesna [10]

Answer:

The observer detects light of wavelength is 115 nm.

(b) is correct option

Explanation:

Given that,

Wavelength of source = 500 nm

Velocity = 0.90 c

We need to calculate the wavelength of observer

Using Doppler effect

\lambda_{o}=\sqrt{\dfrac{1-\beta}{1+\beta}}\lambda_{s}

Where, \beta=\dfrac{c}{v}

\lambda_{o}=\sqrt{\dfrac{c-0.90c}{c+0.90c}}\times500\times10^{-9}

\lambda_{o}=115\ nm

Hence, The observer detects light of wavelength is 115 nm.

8 0
4 years ago
Define volume charge density <img src="https://tex.z-dn.net/?f=%20%28%20%5C%3A%20%5Crho%20%5C%3A%20%29%20" id="TexFormula1" titl
azamat

Answer:

Volume charge density: When the charge density is throughout the volume of a body, then the charge per unit volume is called volume charge density and it is represented by ρ.

∴ρ=

\frac{v}{p}

Hence the unit of ρ is Cm

−3

Example: If a charge q is uniformly distributed in the whole volume of a

sphere of radius R, then p =

\frac{q}{ \frac{4}{3} }  \pi {r}^{3} =3q/4πR-3

3 0
2 years ago
Read 2 more answers
Which of the following is an indicator of good water quality?
Agata [3.3K]
The answer would be: c. High levels of dissolved oxygen

Oxygen is vital for most (aerobic) organism. Fish using oxygen that dissolved in the water so high level of dissolved oxygen will make the fish grow easier. Water with pH of 5 would be an acid water. Acid is corrosive and it can kill some organism that sensitive. High levels of fecal coliform mean the water contaminated with fecal material and must have a high level of bacteria.
6 0
3 years ago
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A person on a diet loses 1.6 kg in a week. How many micrograms/second (µg/s) are lost?
Ivan
Based on the given values above, in order for us to get the answer, we need to convert the units first. So in 1 kilogram, there is 1,000,000 micrograms. In this case, 1.6 kilograms is 1,600,000 micrograms. For the week to seconds, 1 week is equivalent to 604,800 seconds. Therefore, 1,600,000 micrograms/604,800 seconds. So we are going to simplify this. So it would be 2.65<span>µg/s. Hope this answers your question.</span>
8 0
3 years ago
What is the wavelength, in nm, of a photon with energy
lara31 [8.8K]

Answer:

(a)  λ = 4136 nm → infrared

(b) λ = 413.6 nm → visible light

(c) λ = 41.36 nm → ultraviolet

Explanation:

The wavelength of infrared is on the range of 700 nm to 1000000 nm

The wavelength of visible light is between 400 nm and 700 nm

The wavelength of ultraviolet ray on the range of 10 nm to 400 nm

The wavelength of photon is given by;

E = hf

f is the frequency of the wave = c / λ

E = h\frac{c}{\lambda}\\\\ \lambda = \frac{hc}{E}

Where;

c is the speed of light = 3 x 10⁸ m/s

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

(a) 0.3 eV = 0.3 x 1.602 x 10⁻¹⁹ J

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(0.3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-6} \ m

λ = 4136 x 10⁻⁹ m

λ = 4136 nm → infrared

(b) 3.0 eV

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-7} \ m

λ = 413.6 x 10⁻⁹ m

λ = 413.6 nm →visible light

(c) 30 eV

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(30)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-8} \ m

λ = 41.36 x 10⁻⁹ m

λ = 41.36 nm →ultraviolet

5 0
3 years ago
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