1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nutka1998 [239]
2 years ago
12

Ethanol has a heat of vaporization of 38.56kj/mol and a normal boiling point of 78.4 ∘c.

Chemistry
1 answer:
Elanso [62]2 years ago
4 0

This is an incomplete question, here is a complete question.

Ethanol has a heat of vaporization of 38.56 kJ/mol and a normal boiling point of 78.4 °C. What is the vapor pressure of ethanol at 14 °C?

Answer : The vapor pressure of ethanol at 14.0^oC is 5.174\times 10^{-2}atm

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of ethanol at 14.0^oC = ?

P_2 = vapor pressure of ethanol at normal boiling point = 1 atm

T_1 = temperature of ethanol = 14.0^oC=273+14.0=287K

T_2 = normal boiling point of ethanol = 78.4^oC=273+78.4=351.4K

\Delta H_{vap} = heat of vaporization = 38.56 kJ/mole = 38560 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{38560J/mole}{8.314J/K.mole}\times (\frac{1}{287K}-\frac{1}{351.4K})

P_1=5.174\times 10^{-2}atm

Hence, the vapor pressure of ethanol at 14.0^oC is 5.174\times 10^{-2}atm

You might be interested in
A reaction occurs when one compound reacts and is broken down into different elements or simpler compounds.
Inessa [10]

Answer:

Decomposition Reaction

Explanation:

If you are referring to what type of reaction that occurred then the answer would be decomposition reaction.

This is a chemical reaction where one reactant is broken down into two or more products.

REACTANT → PRODUCT

       AB       →      A + B

The products can be two or more elements or two or more compounds, depending on what was decomposed.

3 0
2 years ago
Read 2 more answers
Which of the following is a hypothesis for an experiment measuring solubility of sodium sulfate?
SCORPION-xisa [38]
A would be a hypothesis
7 0
2 years ago
N₂O(g) + 3 H₂(g) N₂H4(1) + H₂O(1) AH = -317 kJ/mol
docker41 [41]

Answer:

A

Explanation:

Recall that Δ<em>H</em> is the sum of the heats of formation of the products minus the heat of formation of the reactants multiplied by their respective coefficients. That is:


\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_{f} \left(\text{Products}\right) - \sum \Delta H^\circ_{f} \left(\text{Reactants}\right)

Therefore, from the chemical equation, we have that:


\displaystyle \begin{aligned} (-317\text{ kJ/mol}) = \left[\Delta H^\circ_f \text{ N$_2$H$_4$} +  \Delta H^\circ_f \text{ H$_2$O}  \right]   -\left[3 \Delta H^\circ_f \text{ H$_2$}+\Delta H^\circ_f \text{ N$_2$O}\right] \end{aligned}

Remember that the heat of formation of pure elements (e.g. H₂) are zero. Substitute in known values and solve for hydrazine:

\displaystyle \begin{aligned} (-317\text{ kJ/mol}) & = \left[ \Delta H^\circ _f \text{ N$_2$H$_4$} + (-285.8\text{ kJ/mol})\right] -\left[ 3(0) + (82.1\text{ kJ/mol})\right] \\ \\ \Delta H^\circ _f \text{ N$_2$H$_4$} & = (-317 + 285.8 + 82.1)\text{ kJ/mol} \\ \\ & = 50.9\text{ kJ/mol} \end{aligned}

In conclusion, our answer is A.

5 0
2 years ago
what mass of carbon dioxide gas would be produced if 10g of calcium carbonate reacted with an excess of hydrochloric acid?
LuckyWell [14K]
Answer is: 4,4 grams <span>of carbon dioxide gas would be produced.
</span>Chemical reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.
m(CaCO₃) = 10 g.
n(CaCO₃) = 10 g ÷ 100 g/mol.
n(CaCO₃) = 0,1 mol.
From chemical reaction: n(CaCO₃) : n(CO₂) = 1 : 1.
n(CO₂) = 0,1 mol.
m(CO₂) = n(CO₂) · M(CO₂).
m(CO₂) = 0,1 mol· 44 g/mol.
m(CO₂) = 4,4 g.
7 0
3 years ago
You put two open cans of soda on the table. You took one can from the refrigerator and the other from your car. When you open th
jarptica [38.1K]
The soda can from the car will lose CO2 more quickly. This is because of the kinetic energy and behavior of gas molecules under different temperatures. CO2 is more soluble in cold temperatures than hot. Cold temperatures minimize the kinetic energy of gas molecules; thus, preventing the gas from escaping the soda. This is why soda that comes from the refrigerator has more fizz or spirit than soda at room temperature.
4 0
3 years ago
Other questions:
  • If a satellite or spaceship explodes in outer space, you can see the explosion from a distance but you cannot hear it. Why?
    9·2 answers
  • How many electrons are transferred between the cation and anion to form the ionic bond in one formula unit of each compound? (1
    6·1 answer
  • 11) When salt and water are mixed, they form a solution like in the ocean. When sand and water are mixed, they form a mixture wh
    9·1 answer
  • What is the change on the subatomic particles represented in Figure 4-3? Assuming all the particles in the nucleus are visible,
    15·2 answers
  • If you have 2.41 × 1024 atoms of copper, how many moles of copper do you have? If you have 2.41 atoms of copper, how many moles
    14·1 answer
  • Which best characterizes a crystal
    15·2 answers
  • PLEASE I WILL PUT YOU AS BRAINLIEST, 20 POINTS
    9·2 answers
  • Do regular Ritz crackers have lipids, glucose, protein, or starch?
    6·2 answers
  • Please fill in the blanks at the bottom!
    9·1 answer
  • 3. What type of reaction is this?<br> Li +<br> H2O -&gt; H2 + LiOH
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!