Given:
Universal set is all positive integers {1,2,3...}
Set A is the set of all positive <u>ODD</u> integers {1,3,5,7...}
The question asks us to find
, which is the <em>complement of set A</em>. The complement of a set refers to elements NOT in that set. Hence, complement of A should be all the elements NOT in A but in Universal Set, U.
It is clear from the question that set A houses all the odd positive numbers, so complement of A will have all the even positive numbers. Last choice is the correct one.
ANSWER:
"{x|x ∈ U and is an even positive integer}"
Answer:
<1 = 109 (Vertically Opposite to <3)
<2 = 71 (Corresponding to <6)
<3 = 109
<4 = 71 (Alternate Interior to <6)
<5 = 109 (Alternate Interior to <3)
<6 = 71
<7 = 109 (Corresponding to <3)
<8 = 71 (Vertically Opposite to <6)
Step-by-step explanation:
<1 = 2x + 29
<2 = x + 31
<3 = 2x + 29
<4 = x + 31
<5 = 2x + 29
<6 = x + 31
<7 = 2x + 29
<8 = x + 31
<1 + <2 = 180
(2x + 29) + (x + 31) = 180
(2x +x) + (29 + 31) = 180
3x + 60 = 180
3x = 180 - 60 = 120
x = 120/3
x = 40
<1 = (2x + 29)
= (2 * 40) + 29
= 80 + 29
= 109
<2 = x + 31
= 40 +31
= 71
Answer:
h
Step-by-step explanation:
x can not repeat itself
What is a justification ? Exactly
Answer:
B
Step-by-step explanation:
The answer is B because the slope is
and there is no y- intercept