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EastWind [94]
3 years ago
13

Why do engineers use metals in making electrical wires

Chemistry
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

Why is copper used for most electrical wiring? All metals have some amount of resistivity to electrical currents, which is why they require a power source to push the current through. The lower the level of resistivity, the more electrical conductivity a metal has

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Compounds in a and b were named incorrectly. On a sheet of paper draw the molecule that fits the given description. From the str
krok68 [10]

Answer:

a. 4—ethyl—5—methyloctane

b. 2,2,6—trimethyloctane

Explanation:Please see attachment for explanation

3 0
3 years ago
How much energy (joules) is needed to heat 250 grams of copper from 22 °C to 99 °C? The specific heat capacity (C) of copper is
Naddik [55]

Answer:

7430.5 Joules (7.4*10^4 Joules)

Explanation:

Q=mc∆T

where Q is energy in Joules.

Now m=250 g

c= 0.386 J/g°C

∆T = 99 - 22 = 77 °C

plugging the values in gives

Q=250*0.386*77=7430.5 Joules

(7.4*10^4 Joules, if 2 significant figures)

5 0
3 years ago
How are fossils formed
creativ13 [48]
I am sure the answer is D
7 0
3 years ago
Solid potassium chlorate decomposes upon heating to form
olga55 [171]

Answer:

32.6%

Explanation:

Equation of reaction

2KClO₃ (s) → 2KCl (s) + 3O₂ (g)

Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)

Molar volume of Oxygen at s.t.p = 22.4L / mol

since the gas was collected over water,

total pressure = pressure of water vapor + pressure of  oxygen gas

0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C

pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1

P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p

Using ideal gas equation

\frac{P1V1}{T1} = \frac{P2V2}{T2}

V2 = \frac{P1V1T2}{T1P2}

V2 = 664.1052 ml

245.2   yielded 67.2 molar volume of oxygen

0.66411 will yield = \frac{245.2 * 0.66411}{67.2}  = 2.4232 g

percentage of potassium chlorate in the original mixture = \frac{2.4232 * 100}{7.44} = 32.6%

3 0
3 years ago
Question 1<br> How many grams are equal to 3.4 moles of carbon dioxide?
ddd [48]

Answer:

149.6 grams

Explanation:

Mass in gram = molar mass * number of moles

Massof CO2 in gram = 44*3.4=149.6 grams

4 0
3 years ago
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