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Natali [406]
3 years ago
12

At stp, a 12.0 liter sample of CH4 has the same total number of molecules as

Chemistry
2 answers:
Elden [556K]3 years ago
5 0

Option 2: 12.0 L of CO_{2} (g) at STP.

The standard pressure and temperature values are 1 atm and 273.15 K.

Using the ideal gas equation, number of moles of gas can be calculated which is as follows:

PV=nRT...... (1)

Here, P is pressure, V is volume, n is number of moles, R is gas constant and T is temperature.

Also, in 1 mole of any gas there are 6.023\times 10^{23} molecules of the gas. This is known as Avogadro's number and denoted by symbol N_{A}

Thus,

N=n\times N_{A}

Equation (1) can be rewritten as follows:

PV=\frac{N}{N_{A}}RT

On rearranging,

N=\frac{P\times V\times N_{A}}{R\times T}

Here, all the other terms are constant except volume, thus, gas with volume equal to the volume of CH_{4} will have same number of molecules.

Volume of CH_{4} gas and CO_{2}gas is same thus, CH_{4} will have same total number of molecules as  CO_{2} gas.


Luba_88 [7]3 years ago
3 0
<span>2 the answer is 12.0 L of CO2(g) at STP</span>
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A compound is found to be 38.76% calcium, 19.97% phosphorous and 41.28% oxygen. What is the empirical formula for this compound?
motikmotik

The empirical formula is Ca₃P₂O₈.

<em>Assume</em> that you have 100 g of the compound.

Then you have 38.76 g Ca, 19.97 g P, and 41.28 g O.

Now, we must convert these <em>masses to moles</em> and <em>find their ratio</em>s.

If the number in the ratio are not close to integers, you <em>multiply them by a numbe</em>r that makes them close to integers.

From here on, I like to summarize the calculations in a table.

<u>Element</u>  <u>Mass/g</u>     <u> Moles  </u>      <u> </u><u>Ratio </u>    <u>   ×2    </u>   <u>Integers</u>  

     Ca       38.76      0.967 07     1.4998   2.9995         3

     P         19.97       0.644 82     1             2                   2

     O        41.28       2.580 0       4.0011   8.0023          8

The empirical formula is Ca₃P₂O₈.


3 0
2 years ago
Write a balanced equation using the correct formulas and include conditions (s, l, g or aq) for each of the following reactions.
Aloiza [94]

Answer:

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Explanation:

Step 1: Data given

iron = Fe = solid = Fe(s)

chlorine = Cl2 = gas = Cl2(g)

iron(III) chloride = FeCl3 = solid = FeCl3(s)

Step 2: The unbalanced equation

Fe(s) + Cl2(g) → FeCl3(s)

Step 3: Balancing the equation

Fe(s) + Cl2(g) → FeCl3(s)

On the left we have 2x Cl (in Cl2) and on the right side we have 3x Cl (in FeCl3). To balance the amount of Cl we have to multiply Cl2 (on the left) by 3 and FeCl3 by 2.

Fe(s) + 3Cl2(g) → 2FeCl3(s)

On the left side we have 1x Fe and on the right side we have 2x Fe (in 2FeCl3). To balance the amount of Fe, we have to multiply Fe on the left side by 2. Now the equation is balanced.

2Fe(s) + 3Cl2(g) → 2FeCl3(s)

6 0
3 years ago
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