<span>The atomic weight of silver is 107.8682</span>
Hey there !
The answer would be C. Is when electrons cannot nice through objects easily.
Any material that keeps energy such as electricity, heat, or cold from easily transferring through is an insulator. Wood, plastic, rubber, and glass are good insulators.
Hope this helps !
The empirical formula is Ca₃P₂O₈.
<em>Assume</em> that you have 100 g of the compound.
Then you have 38.76 g Ca, 19.97 g P, and 41.28 g O.
Now, we must convert these <em>masses to moles</em> and <em>find their ratio</em>s.
If the number in the ratio are not close to integers, you <em>multiply them by a numbe</em>r that makes them close to integers.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u> Moles </u> <u> </u><u>Ratio </u> <u> ×2 </u> <u>Integers</u>
Ca 38.76 0.967 07 1.4998 2.9995 3
P 19.97 0.644 82 1 2 2
O 41.28 2.580 0 4.0011 8.0023 8
The empirical formula is Ca₃P₂O₈.
Answer:
2Fe(s) + 3Cl2(g) → 2FeCl3(s)
Explanation:
Step 1: Data given
iron = Fe = solid = Fe(s)
chlorine = Cl2 = gas = Cl2(g)
iron(III) chloride = FeCl3 = solid = FeCl3(s)
Step 2: The unbalanced equation
Fe(s) + Cl2(g) → FeCl3(s)
Step 3: Balancing the equation
Fe(s) + Cl2(g) → FeCl3(s)
On the left we have 2x Cl (in Cl2) and on the right side we have 3x Cl (in FeCl3). To balance the amount of Cl we have to multiply Cl2 (on the left) by 3 and FeCl3 by 2.
Fe(s) + 3Cl2(g) → 2FeCl3(s)
On the left side we have 1x Fe and on the right side we have 2x Fe (in 2FeCl3). To balance the amount of Fe, we have to multiply Fe on the left side by 2. Now the equation is balanced.
2Fe(s) + 3Cl2(g) → 2FeCl3(s)