Answer:
68 grams
Explanation:
Reaction that produces ammonia when nitrogen and hydrogen reacts is given by :-
+ 3
→ 2N
Clearly ,
When one mole of nitrogen reacts , two moles of ammonia will be produced.
Now,
weight of 1 mole of the Nitrogen = 28.0 grams
In 56.0 grams of the nitrogen , two moles will be present.
Thus , 4 moles of ammonia will be produced .
Weight of one mole of nitrogen = 17 grams.
Thus a total of 17× 4 = 68 grams f nitrogen will be produced.
Answer:
A. Do not change their energy level.
Explanation:
The process in which a solid changes directly to a gas is called sublimation. It occurs when the particles of a solid absorb enough energy to completely overcome the force of attraction between them. Dry ice (solid carbon dioxide, CO2) is an example of a solid that undergoes sublimation.
Answer: 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
Explanation:
To calculate the moles :
![\text{Moles of} C_8H_{18}=\frac{350g}{114g/mol}=3.07moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%7D%20C_8H_%7B18%7D%3D%5Cfrac%7B350g%7D%7B114g%2Fmol%7D%3D3.07moles)
According to stoichiometry :
As 2 moles of octane give = 16 moles of ![CO_2](https://tex.z-dn.net/?f=CO_2)
Thus 3.07 moles of octane will give =
of ![CO_2](https://tex.z-dn.net/?f=CO_2)
Mass of ![CO_2=moles\times {\text {Molar mass}}=24.6moles\times 44g/mol=1082g](https://tex.z-dn.net/?f=CO_2%3Dmoles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D24.6moles%5Ctimes%2044g%2Fmol%3D1082g)
Thus 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
1.5 = 1500g/Volume
Rearrange the equation:
Volume = 1500/1.5 = 1000
So your answer is 3. 1000 cm3