Answer:
One may conclude that they have an identical number of electrons in their outermost shell, therefore the can be substituted for one another.
Explanation:
Elements in the same family tend to behave similarly in chemical reactions because they have similar number of valence electrons in their outermost shell and they also have similar chemical properties.
Valence electrons are responsible for reactions between elements. The valence electron makes it possible for atoms to combine and react, therefore, elements in a family behave similarly in chemical reactions because they have an identical number of electrons in their outermost shell.
Answer:
a) 64.27%
b) 58%
c) ethanol is the limiting reactant
d) ethanol is the limiting reactant
Explanation:
We have to note that the expected yield is the theoretical yield while the actual mass or amount of product formed is the actual yield.
a) theoretical yield=68.3g
Actual yield= 43.9 g
Percentage yield= 43.9/68.3 ×100
Percentage yield= 64.27%
b) theoretical yield= 0.0722 moles
Actual yield = 0.0419
Percentage yield= 0.0419/0.0722 × 100
Percentage yield= 58%
c) note that the limiting reactant yields the least number of moles of product
Ethanol will be the limiting reactant since it is not present in excess.
d) from the reaction equation;
1 mole of acetic acid produces 1 mole of ethyl acetate
0.58 moles of ethanol produces 0.58 moles of ethyl acetate
1 mole of acetic acid yields 1 mole of ethyl acetate
Hence 0.82 moles of acetic acid yields 0.82 moles of ethyl acetate
Hence ethanol is the limiting reactant.
Air does move from high to low pressure so true
Metalloids are all solid at room temperature<span>. Some metalloids, such as silicon and germanium, can act as </span>electrical<span> conductors under the right conditions, thus they are called semiconductors. Silicon, for example, appears lustrous but is not malleable or </span>ductile<span> (it is brittle - a characteristic of some nonmetals).
If this helped, please give me brainliest :)</span>
The balanced chemical reaction is:
C4H10 + 5O2 = 4CO2 + 2H2O
We are given the amount of butane to be used in the reaction. This will be the starting point of the calculations.
2.50 g C4H10 ( 1 mol C4H10 / 58.14 g C4H10) ( 4 mol CO2 / 1 mol C4H10 ) = 0.21 mol CO2
V = nRT / P = 0.21 mol CO2 (0.08206 atm L/mol K) 320.15 K / 1.04 atm = 5.30 L CO2