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irinina [24]
3 years ago
13

A 20 N force is applied to an object causing it to move 10 m. How much work was done on the object? How much energy was needed t

o move the object?
Physics
1 answer:
olga2289 [7]3 years ago
3 0

Answer:

Here, force=20N and displacement=10m

Work=Force×Displacement=20N×10m=200Nm

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explain how a large force is exerted on a passenger in a vehicle in the event of a car crash and how this can be reduced.
xeze [42]
Using idea of conservation of impulse-momentum theorem, the instantaneous velocity times mass is equal to force times the change in time.

mv = Ft

To reduce the force, decrease the velocity and mass. You can also extend the time of the collision. This is why cars collapse on impact. They were design that way to reduce the force on the car and the passenger.

Hopes this helps!
5 0
3 years ago
A horizontal force of 12 Newtons is applied to a 4.0 kg box that slides on a horizontal surface. The box starts from rest moves
Serjik [45]

Answer:

7.0N

Explanation:

F=ma

v2=u2+2as

25=0+20a

a=1.25m/s2

F=ma

F=0.4×1.25

Fn=5N

F=12

12-5=Ff

=7.0N

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3 years ago
All but one statement applies to electromagnetic radiation
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<span>D) Electromagnetic radiation travels in the form of longitudinal waves.</span>
3 0
3 years ago
A projectile is fired at an upward angle of 45.0º from the top of a 265-m cliff with a speed of .sm 185 What will be its speed w
nignag [31]

The final velocity of the projectile when it strikes the ground below is 198.51 m/s.

<h3>Time of motion of the projectile</h3>

The time taken for the projectile to fall to the ground is calculated as follows;

h = vt + ¹/₂gt²

where;

  • h is height of the cliff
  • v is velocity
  • t is time of motion

265 = (185 x sin45)t + (0.5)(9.8)t²

265 = 130.8t + 4.9t²

4.9t² + 130.8t - 265 = 0

solve the quadratic equation using formula method,

t = 1.89 s

<h3>Final velocity of the projectile</h3>

vyf = vyi + gt

where;

  • vyf is the final vertical velocity
  • vyi is initial vertical velocity

vyf = (185 x sin45) + (9.8 x 1.89)

vyf = 149.322 m/s

vxf = vxi

where;

  • vxf is the final horizontal velocity
  • vxi is the initial horizontal velocity

vxf = 185 x cos(45)

vxf = 130.8 m/s

vf = √(vyf² + vxf²)

where;

  • vf is the speed of the projectile when it strikes the ground below

vf = √(149.322²  +  130.8²)

vf = 198.51 m/s

Learn more about final velocity here: brainly.com/question/6504879

#SPJ1  

3 0
3 years ago
Between two objects.
Ira Lisetskai [31]

Answer:

C Friction

Explanation:

6 0
3 years ago
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