Answer:
UMm If i understood ide answer
Explanation:
Answer:
Magnetic field, ![B=2.55\times 10^{-14}\ T](https://tex.z-dn.net/?f=B%3D2.55%5Ctimes%2010%5E%7B-14%7D%5C%20T)
Explanation:
It is given that,
Speed of proton, ![v=4\times 10^6\ m/s](https://tex.z-dn.net/?f=v%3D4%5Ctimes%2010%5E6%5C%20m%2Fs)
Mass of the proton, ![m=1.67\times 10^{-27}\ kg](https://tex.z-dn.net/?f=m%3D1.67%5Ctimes%2010%5E%7B-27%7D%5C%20kg)
Charge on proton, ![q=1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=q%3D1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
We need to find the magnetic field strength required to just balance the weight of the proton and keep it moving horizontally.
The Lorentz force is given by :
.............(1)
The weight of proton,
..............(2)
From equation (1) and (2), we get :
![mg=qvB](https://tex.z-dn.net/?f=mg%3DqvB)
![B=\dfrac{mg}{qv}](https://tex.z-dn.net/?f=B%3D%5Cdfrac%7Bmg%7D%7Bqv%7D)
![B=\dfrac{1.67\times 10^{-27}\ kg\times 9.8\ m/s^2}{1.6\times 10^{-19}\ C\times 4\times 10^6\ m/s}](https://tex.z-dn.net/?f=B%3D%5Cdfrac%7B1.67%5Ctimes%2010%5E%7B-27%7D%5C%20kg%5Ctimes%209.8%5C%20m%2Fs%5E2%7D%7B1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C%5Ctimes%204%5Ctimes%2010%5E6%5C%20m%2Fs%7D)
![B=2.55\times 10^{-14}\ T](https://tex.z-dn.net/?f=B%3D2.55%5Ctimes%2010%5E%7B-14%7D%5C%20T)
Hence, this is the required solution.
Answer:
A
Explanation:
Can read mass precisely, commonly reading error of +0.05g
Answer:A)0.5 and 2 mm
Explanation:
Given
radius R of wire is 1 mm
magnetic Field at edge(surface) ![=10^{-5} T](https://tex.z-dn.net/?f=%3D10%5E%7B-5%7D%20T)
Magnetic Field at a distance r' from Center is ![B'=5\times 10^{-6} T](https://tex.z-dn.net/?f=B%27%3D5%5Ctimes%2010%5E%7B-6%7D%20T)
and we know
![B=\frac{\mu _0I}{2\pi r}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu%20_0I%7D%7B2%5Cpi%20r%7D)
where ![I= current](https://tex.z-dn.net/?f=I%3D%20current%20)
Permeability of free space
distance from center
For ![r=R](https://tex.z-dn.net/?f=r%3DR)
---1
For ![r=r'](https://tex.z-dn.net/?f=r%3Dr%27)
---2
Divide 1 and 2
![\frac{10^{-5}}{0.5\times 10^{-5}}=\frac{r'}{R}](https://tex.z-dn.net/?f=%5Cfrac%7B10%5E%7B-5%7D%7D%7B0.5%5Ctimes%2010%5E%7B-5%7D%7D%3D%5Cfrac%7Br%27%7D%7BR%7D)
![r'=2 R=2 mm](https://tex.z-dn.net/?f=r%27%3D2%20R%3D2%20mm%20)
If r is inside the wire then
![B=\frac{\mu _0rI}{2\pi R^2}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu%20_0rI%7D%7B2%5Cpi%20R%5E2%7D)
for ![r=R](https://tex.z-dn.net/?f=r%3DR)
---3
for ![r=r"](https://tex.z-dn.net/?f=r%3Dr%22)
----4
Divide 3 and 4
![2=\frac{R}{r"}](https://tex.z-dn.net/?f=2%3D%5Cfrac%7BR%7D%7Br%22%7D)
![r"=0.5 mm](https://tex.z-dn.net/?f=r%22%3D0.5%20mm)