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3 years ago

When you cut a board with a power saw as compared with a handsaw, how much work do you do with the power saw?

Physics

2 answers:

Bezzdna [24]3 years ago

8 0

A) less work in less time

oee [108]3 years ago

7 0

I believe the answer is A) Less work in less time.

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Properties of elements within a ______________on the periodic table change in a predictable way from one side of the table to th

Natalka [10]

Answer: Period

Explanation: Properties of elements within a period on the periodic table change in a predictable way from one side of the table to the other. A period in the periodic table is a horizontal row. All elements in a row have the same number of electron shells.

8 0

3 years ago

Which of the following lists the stars in order from least density to greatest density?

BARSIC [14]

The following lists of stars in order from least density to greatest density are giant, main sequence star, white dwarf, neutron star. The answer is letter B. Aside from neutron star being the densest star, it is also the smallest star compared to the giant star, as its name implied.

6 0

3 years ago

Thirty beats are heard in one minute when two notes are played together. If the higher note has a frequency of 740 Hz, what is t

Tatiana [17]

30 beats/1min = 30 beats/60 sec = .5 beat/sec = 1/2 Hz
740 Hz - 1/2 Hz = 739.5 Hz

Answer - c. 739.5 Hz

6 0

3 years ago

A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres

Lemur [1.5K]

Answer:

$V_2 = 0.125 m^3$

Work done = = 5 kJ

Explanation:

Given data:

volume of nitrogen $v_1 = 0.08 m^3$

$P_1 = 150 kPa$

$T_1 = 200 degree celcius = 473 Kelvin$

$P_2 = 80 kPa$

Polytropic exponent n = 1.4

$\frac{T_2}{T_1} = [\frac{P_2}{P_1}]^{\frac{n-1}{n}$

putting all value

$\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}$

$\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS$

polytropic process is given as

$P_1 V_1^n = P_2 V_2^n$

$150\times 0.08^{1.4} = 80 \times V_2^{1.4}$

$V_2 = 0.125 m^3$

work done $= \frac{P_1 V_1 -P_2 V_2}{n-1}$

$= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}$

= 5 kJ

4 0

3 years ago

A 2.40 kg stone is sliding in the +x-direction on a horizontal, frictionless surface. It collides with a 4.00 kg stone at rest.

tester [92]

Answer:

4.32 kg.m/s

Explanation:

SInce the 2.4 kg stone is mobing at speed of 3.6m/s at an angle of 30 degree measured from the x+ direction toward y+ direction. Its y-component momentum is product of its velocity in the y-direction and its mass

$P_y = m*v_y = m*v*sin(\theta)$

$P_y = 2.4*3.6*sin(30)$

$P_y = 2.4*3.6*0.5 = 4.32 kg.m/s$

5 0

3 years ago