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3 years ago

What's the electron configuration of an N-3 ion?

Chemistry

1 answer:

WARRIOR [948]3 years ago

8 0

Answer:

A. since Nitrogen has 7 electrons and when it gains 3 electrons it will have 10 electrons. using short hand rule it is [Ne]

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Which best describes the transfer of heat energy through conduction? A. Heat energy is transferred from molecule to molecule by

TiliK225 [7]

It should be option (A) because conduction is the transfer of heat energy from one place to another by vibrations/motion of the molecules. I hoped I helped.

5 0

3 years ago

A solution contains 22.4 g glucose (C6H12O6 ) dissolved in 0.500 L of water. What is the molality of the solution

Shalnov [3]

Answer:

Molality is 0.25 m

Explanation:

Molality → Moles of solute / kg of solvent

We need the moles of solute → 0.124 moles

22.4 g . 1 mol / 180 g = 0.124 moles

We need the mass of solvent in kg. We determine the mass of solvent with density.

Density = Mass / Volume

Mass = Density . volume → 1 g/mL . 500 mL = 500 g

If we convert the mass in g to kg → 500 g . 1kg / 1000 g = 0.5 kg

In conclussion, molality → 0.124 mol / 0.5 kg = 0.25 m

8 0

3 years ago

4.<br>How many parents take part in binary fission?

Sladkaya [172]

Binary fission is done by one parent . as one parent cell divides it into two daughter cells and further.

7 0

3 years ago

Read 2 more answers

What is the scientific notation of 68000

Kaylis [27]

68000 = 6.8 * 10000 = 6.8 * 10^4

hope this helps? c;

3 0

3 years ago

What heavier element is created when hydrogen atoms fuse together in the sun’s core?

sergey [27]

Answer:

Helium is created from hydrogen in the sun's core.

Four hydrogen-1 nuclei fuse to produce

one helium-4 nucleus, two neutrons,
two positrons, and
two electron neutrinos.

Explanation:

Step One:

${\rm ^1_1 H + ^1_1 H\to ^2_1 H + e^{+}} + v_e$ .

Two hydrogen-1 nuclei fuse. One proton will convert to a neutron. The products will be

one hydrogen-2 nucleus,
one positron, and
one electron neutrino.

Step Two:

$\rm ^1_1 H +^2_1 H \to ^3_2 He$ .

There are plenty of hydrogen-1 nuclei available in the core of the sun. The hydrogen-2 nucleus from step one will fuse with a hydrogen-1 nucleus. The product is

one helium-3 nucleus.

Step Three

$\rm ^3_2 He + ^3_2 He \to ^4_2 He + ^1_1 H + ^1_1 H$ .

Two helium-3 nuclei from step two react with each other. The products are:

one helium-4 nucleus, and
two hydrogen-1 nuclei.

The overall reaction will be:

${\rm 6\; ^1_1 H \to ^4_2 He + 2\; ^1_1 H+2\; e^{+}}+v_\text{e}$ .

${\rm 4\; ^1_1 H \to ^4_2 He + 2\; e^{+}} + v_\text{e}$

In other words, hydrogen nuclei in the core of the sun fuse together to form helium.

6 0

3 years ago