Question

!!Help!!

Answer 1

Answer:

s = 37.81 m

Explanation:

Given that,

Mass of an apple, m = 1.5 kg

The apple falls for 2.75s before striking the ground.

We need to find how far the apple dropped before hitting the ground. It means we need to find the distance covered. Using the second equation of motion to find it :

$s=ut+\dfrac{1}{2}gt^2$

u is initial velocity, u = 0 (at rest)

$s=\dfrac{1}{2}gt^2\\\\s=\dfrac{1}{2}\times 10\times (2.75)^2\\\\=37.81\ m$

So, Apple dropped 37.81 m before hitting the ground.