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Y_Kistochka [10]
3 years ago
8

!!Help!!

Physics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

s = 37.81 m

Explanation:

Given that,

Mass of an apple, m = 1.5 kg

The apple falls for 2.75s before striking the ground.

We need to find how far the apple dropped before hitting the ground. It means we need to find the distance covered. Using the second equation of motion to find it :

s=ut+\dfrac{1}{2}gt^2

u is initial velocity, u = 0 (at rest)

s=\dfrac{1}{2}gt^2\\\\s=\dfrac{1}{2}\times 10\times (2.75)^2\\\\=37.81\ m

So, Apple dropped 37.81 m before hitting the ground.

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Well we know the correct answer cannot be "a" bcause velocity is tangent to the circlular path of an object experienting centripical motion. Velocity DOES NOT point inward in centripical motion.

we know the correct answer cannot be "b" because "t" stands for "time" which cannot point in any direction. so, time cannot point toward the center of a circle and therefore this answer must be incorrect.

I would choose answer choice "c" because both force and centripical acceleration point toward the center of the circle.

I do not think answer choice "d" can be correct because the velocity of the mass moves tangent to the circle. velocity = (change in position) / time. Therefore, by definition the mass is moving in the direction of the velocity which does not point to the center of the circle.

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Nesterboy [21]

Answer:

<em>The velocity after the collision is 2.82 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

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There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.

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\displaystyle v'=\frac{3.91*5.7+4*0}{3.91+4}

\displaystyle v'=\frac{22.287}{7.91}

\boxed{v' = 2.82\ m/s}

The velocity after the collision is 2.82 m/s

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