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Y_Kistochka [10]
3 years ago
8

!!Help!!

Physics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

s = 37.81 m

Explanation:

Given that,

Mass of an apple, m = 1.5 kg

The apple falls for 2.75s before striking the ground.

We need to find how far the apple dropped before hitting the ground. It means we need to find the distance covered. Using the second equation of motion to find it :

s=ut+\dfrac{1}{2}gt^2

u is initial velocity, u = 0 (at rest)

s=\dfrac{1}{2}gt^2\\\\s=\dfrac{1}{2}\times 10\times (2.75)^2\\\\=37.81\ m

So, Apple dropped 37.81 m before hitting the ground.

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Bob and John are pulling in different directions. If Bob is pulling to the right with a force of 10N, and John is pulling to the
Oksi-84 [34.3K]

-- The net force on the box is 2N to the left.

-- The box will move to the left and accelerate to the left.

-- F=ma . a=F/m . a=(2N)/(4kg).

a = 0.5 m/s^2 to the left.

5 0
3 years ago
A 94.7 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.75 r
Marta_Voda [28]

Answer:

The angular velocity of the platform is 1.114 rad/s.

Explanation:

Step 1:  Given data

Mass of the horizontal circular platform = 94.7 kg

Mass of the monkey = 21.1 kg

Initial angular velocity = 1.75 rad/s

A monkey drops a 9.25 kg bunch of bananas

They hit the platform at 4/5 of its radius from the center

Model the platform as a disk of radius 1.63 m

Step 2: Calculate the moment of inertia of the disk

I = ½ * m * r² = ½ * 94.7 * 1.63² = 125.80

Step 3: Calculate the initial angular momentum

I = 125.80 * 1.75 = 220.15

Step 4: Calculate the moment of inertia for the bananas

For the bananas, r = 4/5 * 1.63 = 1.304 m

I = 9.25 * 1.304² = 15.73

Step 5: Calculate Moment of inertia for the monkey

I = 21.1 * 1.63² = 56.06

Step 6: Total moment of inertia = 125.80 + 15.73 + 56.06 = 197.59

Step 7: Calculate final angular momentum = 197.59 * ω

197.59 * ω = 220.15

ω = 220.15 / 197.59

This is approximately 1.114 rad/s.

3 0
3 years ago
A person stands on the ball of one foot. The normal force due to the ground pushing up on the ball of the foot has magnitude 750
White raven [17]

Answer:

the force exerted on the foot by the tibia would be 2975 N

Explanation:

Given the data in the question;

To maintain equilibrium between the foot and the ball vertically, the addition normal normal force N^> (750 N)  and the tension in the Achilles tendon F^>_{Achilles} (2225 N) must be equal to the force exerted on the foot by the tibia;

so

| N^> | + |F^>_{Achilles} | = | F^>_{Tibia} |

so force exerted on the foot by the tibia will be;

| F^>_{Tibia} | = |N^> | + |F^>_{Achilles} |

so we substitute IN OUR VALUES

| F^>_{Tibia} | = 750 N + 2225 N

| F^>_{Tibia} |  = 2975 N

Therefore, the force exerted on the foot by the tibia would be 2975 N

3 0
3 years ago
Which of the following is a scalar quantity?
makvit [3.9K]

The only scalar quantity is a. 35 m

Explanation:

In physics, there are two types of quantities:

- Scalar: a scalar quantiy is a quantity having only a magnitude, so it is just a number followed by a unit. Examples of scalar quantities in physics are:

Speed

Energy

Distance

Time

- Vector: a vector quantity is quantity having both a magnitude and a direction. Examples of vector quantities in physics are:

Velocity

Force

Acceleration

Displacement

Let's now analyze each given option, to evaluate if it is a scalar or a vector:

a. 35m  --> it is only a unit (no direction), so it is a scalar

b. 20 m to the right  --> it has a direction, so it is a vector

c. 30 m to the North --> it has a direction, so it is a vector

So, the only correct option is a).

Learn more about scalars and vectors:

brainly.com/question/2678571

brainly.com/question/4945130

#LearnwithBrainly

4 0
3 years ago
At the bottom of the ocean, a rock has a mass 25 g. At sea level, the same rock will have a mass of: less than 25 g, more than 2
storchak [24]
It will be same 25 g
5 0
3 years ago
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