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vfiekz [6]
3 years ago
14

(b) Find the position, velocity, and acceleration of the mass at time t = 5π/6.

Physics
1 answer:
Juli2301 [7.4K]3 years ago
4 0
Solution 
x(t) = 8 cos t, x(5π/6)= 8 cos(<span>5π/6)
</span>cos(5π/6)=cos(3π/6 + 2π/6 )=cos(π/3 +π/2)= - sin π/3  (cos (x+<span>π/2)= -sinx)
</span>x(t) = -8sin <span>π/3 = - 4 .sqrt3
</span>v(t) = -8sint = -8sin (π/3 +<span>π/2)= -8 cosπ/3 </span>(sin (x+π/2)= cosx)
v(t) =<span> -8 cosπ/3 = -8/2= - 4 
</span>a(5π/6) = - 8cost = -(- sin π/3)= 4 .<span>sqrt3
</span>a(5π/6) =  4 .<span>sqrt3</span>
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A coffee filter of mass 1.2 grams dropped from a height of 1 m reaches the ground with a speed of 0.8 m/s. How much kinetic ener
iren [92.7K]

<u>Answer:</u> The energy gained by the air molecules is 0.011 J.

<u>Explanation:</u>

Law of conservation of energy states that energy can neither be created nor be destroyed but it can only be transformed from one form to another form.

Here, the potential energy of the coffee filter is getting converted into kinetic energy of the coffee filter and some energy is lost by it which is gained by the air molecules in the form of kinetic energy.

So, calculating the potential energy of coffee filter, we use the equation:

P = mgh

where,

m = mass of coffee filter = 1.2 g = 1.2\times 10^{-3}kg    (Conversion used: 1 kg = 1000 g)

g = acceleration due to gravity = 9.8m/s^2

h = height of coffee filter = 1 m

Putting values in above equation, we get:

P=1.2\times 10^{-3}kg\times 9.8m/s^2\times 1m\\\\P=1.176\times 10^{-2}J

  • Calculating the kinetic energy of coffee filter, we use the equation:

E=\frac{1}{2}mv^2

where,

m = mass of coffee filter = 1.2 g = 1.2\times 10^{-3}kg

v = speed of coffee filter = 0.8 m/s

Putting values in above equation, we get:

E=\frac{1}{2}\times 1.2\times 10^{-3}kg\times (0.8m/s)^2\\\\E=3.84\times 10^{-4}J

As, energy lost by coffee filter = energy gained by air molecules

So, energy lost by coffee filter = Potential energy - Kinetic energy

Energy lost by coffee filter = (1.176\times 10^{-2})-(3.84\times 10^{-4})=0.011J

Hence, the energy gained by the air molecules is 0.011 J.

5 0
3 years ago
How many milligrams are equal to 8 grams?
Andre45 [30]

Answer:

it should be 8,000

Explanation:

because if you multiply the mass value by 1000, you will get 8,000  

:):):):)

6 0
4 years ago
After the box comes to rest at position x₁, a person starts pushing the box, giving it a speed v₁. When the box reaches position
Vesna [10]

Answer:

W_p = \frac{1}{2}mv_1^2

Explanation:

As we know that box is initially at rest

So we will have

v_i = 0

now as it will be displaced from initial position to final position then final speed of the box is reached to

v_f = v_1

now we know by work energy theorem that work done by all the forces on the box will be equal to the change in kinetic energy

So here we will have

W_p = \frac{1}{2}m(v_f^2 - v_i^2)

W_p = \frac{1}{2}m(v_1^2 - 0)

W_p = \frac{1}{2}mv_1^2

8 0
3 years ago
How can a large construction project impact water quality, supply or flow?
Korolek [52]

Answer:

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Explanation:

Hope This Could be of some use

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6 0
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