Boiling point of a solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water. kB= 0.512 c/m.
1 answer:
100.133 degree celsius is the boiling point of the solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water.
Explanation:
Balanced eaquation for the reaction
CaCl2 + 2H20 ⇒ Ca(OH)2 + HCl
given:
mass of CaCl2 = 15.2 grams
mass of the solution = 57 grams
Kb (molal elevation constant) = 0.512 c/m
i = vont hoff factor is 1 as 1 mole of the substance is given as product.
Molality is calculated as:
molality =
=
= 0.26 M
Boiling point is calculated as:
ΔT = i x Kb x M
= 1 x 0.512 x 0.26
= 0.133 degrees
The boiling point of the solution will be:
100 degrees + 0.133 degrees (100 degrees is the boiling point of water)
= 100.133 degree celcius is the boiling point of mixture formed.
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<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is HCl.
are the n-factor, molarity and volume of base which is
We are given:
Putting values in above equation, we get:
To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:
Molarity of solution = 0.011 M
Volume of solution = 36.0 mL
Putting values in above equation, we get:
1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.
Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles
Hence, the moles of hydroxide ions present in the sample is 0.0008 moles
The molecular formula of the given compound is also known as Carbonic acid.
The simplest whole-number ratio of the various atoms in a compound is represented by an empirical formula.
The precise number of various atom types present in a compound's molecule is indicated by the molecular formula.
Given that,
H = 3.3%
C = 19.3%
O = 77.4%
No. of moles of H = 3.3/1
No. of moles of H = 3.3
No. of moles of C = 19.3 / 12
No. of moles of C = 1.60
No. of moles of O = 77.4/16
No. of moles of O = 4.83
Therefore, the ratio of the atoms of C, H and O = 3.3 : 1.60 : 4.83
Divide by smallest value which you get =3.3 / 1.60 : 1.60 / 1.60 : 4.83 / 1.60
The ratio of the atoms of C, H and O = 2 : 1 : 3
So, the empirical formula is
Let the molecular formula is
Then, molar mass
Molar mass = 62n
As the question, 62 n = 60
n = 0.96 or n = 1 (rounded off to nearest ones)
So, the molecular formula is i.e., the compound is Carbonic acid.
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