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Otrada [13]
3 years ago
9

An unknown solid weighs 31.6 n. when submerged in water, its apparent weight is 19.8 n. what is the specific gravity of the unkn

own sample?
Physics
1 answer:
KATRIN_1 [288]3 years ago
6 0

specific gravity of the unknown sample = 2.68

Explanation:

True weight of solid=31.6 N

Apparent weight=19.8 N

loss in weight= 31.6-19.8=11.8 N

Loss in weight= weight of the liquid displaced

so weight of water displaced= 11.8 N

now specific gravity= weight of object/ weight of liquid displaced

specific gravity= 31.6/11.8

specific gravity= 2.68

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The height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.

<h3>Pressure and temperature at equilibrium </h3>

The relationship between pressure and temperature can be used to determine the height risen by the water.

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Thus, the height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.

The complete question is below:

A diving bell is a 4.2 m -tall cylinder closed at the upper end but open at the lower end. The temperature of the air in the bell is 20 °C. The bell is lowered into the ocean until its lower end is 100 m deep. The temperature at that depth is 10°C. How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium?

Learn more about thermal equilibrium here: brainly.com/question/9459470

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