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2 years ago

6

Help me with this problem please please:):)

1 answer:

Lady_Fox [76]2 years ago

6 0

I believe it is 12.5 :)

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Jills fish weighs 8 times as much as her parakeet. Together the pets weigh 63 ounces. How much does the fish way

AVprozaik [17]

63×8 =504 because you are using repeated addition r just regular multiplication

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2 years ago

23. A grid shows the positions of a subway stop and your house. The subway stop is located at (-5, 2) and your house is located

Sindrei [870]

(-5, 2)(-9,9)
D = √( (x2 - x1)^2 + (y2 - y1)^2 )
D = √( (-9+5)^2 + (9 - 2)^2 )
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D = √( 16 + 49 )
D = √65
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3 years ago

If sin theta = -1/2 and lies in the third quadrant, what is the cos?

never [62]

Sin angle that equals the 1/2 value is the 30 degree on the 1st Quadrant.

The angle of 30 degree on the 3rd Quadrant is equivalent to (formula and circle in the 1st photo) 180 + 30 = 210°.

So theta = 210° (3rd Quadrant) = 30° (1st Quadrant).

$cos \: 30\degree = \sqrt{3} \div 2$

Now just transfer the cos 30° to the 3rd Quadrant and the signal will be negative (as shown in the 2nd photo attached).

$cos \: 210 \degree = - \sqrt{3} \div 2$

5 0

3 years ago

Need to be able to check this assignment for my son and I have no clue how to make sure it's correct anyone?

saw5 [17]

Answer:

it is correct

Step-by-step explanation:

4 0

2 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

3 years ago