All categories

3 years ago

Help me with this problem please please:):)

Mathematics

1 answer:

Lady_Fox [76]3 years ago

6 0

I believe it is 12.5 :)

You might be interested in

How do you graph y=7/2x-2

RoseWind [281]

You can either make a table using any numbers you would like (I would suggest -5 to 5) and then graphing the rule

ex. (7/2)(-5)-2 = -19.5 (I multiplied (7/2) by -5 and then subtracted 2)

Or you can put the rule in a graphing calculator and check the points from there

8 0

3 years ago

Answer the question provided in the picture below.

FromTheMoon [43]

Answer:

Finding area: multiply length by width (multiply the top length by the side length)

Finding perimeter: Add the lengths of all of the sides together

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve each proportion ; b/5= 8/16 ( those are fractions)

Alex Ar [27]

The answer is 2.5 just set it up and cross multiply then divide

6 0

4 years ago

Pls help need it ASAP

vitfil [10]

Answer:

3x-2y=17........(1)

x=4y-1

substituting value of x in equation 1

3(4y-1)-2y=17

12y-3-2y=17

10y=17+3

y=20/10=2

again

substituting value of y in equation 1

3x-2×2=17

3x=17+4

x=21/3=7

:.x=7,y=2

3 0

3 years ago

Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa

barxatty [35]

$z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}$

We're given that $f_x(6,1)=3$ and $f_y(6,1)=-1$ , and want to find $\frac{\partial z}{\partial v}(1,2)$ .

By the chain rule, we have

$\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}$

and

$\dfrac{\partial x}{\partial v}=2v$

$\dfrac{\partial y}{\partial v}=-1$

Then

$\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)$

(because the point $(x,y)=(6,1)$ corresponds to $(u,v)=(1,2)$ )

$\implies\dfrac{\partial z}{\partial v}(1,2)=3\cdot2\cdot2+(-1)\cdot(-1)=\boxed{13}$

4 0

3 years ago