3 years ago

Help me with this problem please please:):)

1 answer:

6 0

I believe it is 12.5 :)

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Serhud [2]

Answer:

Step-by-step explanation:

A) $(tanx-4)(9sin^2x-1)=0\\\\\\$

$9sin^2x-1=0\\\\sin^2x=\frac{1}{9} sinx=\frac{1}{3}$ or $sinx=\frac{-1}{3}$

OR $tanx=4\\$

$3sin2x=3.2.sinx.cosx\\\\6.sinx.cosx-4.sinx= 2sinx.(3cosx-2)=0\\\\3.cosx=2 cosx=\frac{2}{3}$

3 0

3 years ago

faust18 [17]

No thanks. Thanks for the point

5 0

3 years ago

masha68 [24]

Answer:

A) (x + 2)

Step-by-step explanation:

x^2 + 5x + 6

=(x +3)(x +2)

so (x+3) and (x+2) are the factors

7 0

3 years ago

Svetach [21]

Do lulus way. If you change the angles, you will not have a pentagon anymore. If you subtract, it wouldn’t be the same ratio:)

8 0

3 years ago

Aleks04 [339]

11 times with a remainder of 5

7 0

3 years ago