Answer:
In his house
Step-by-step explanation:
(3) has answer 7 and (4) is sqrt(32).
x=0, x=-10, x=11
i think it's right - hope i helped! :)
The number of combinations of 2 health care providers of different types possible are 47.
<u>Explanation:</u>
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Doctors = 4
Dentists = 3
Nurses = 5
combinations of two different health care providers = ?
Combination would be = ⁴C₁ X ³C₁ + ³C₁ X ⁵C₁ + ⁴C₁ X ⁵C₁
ⁿCₐ = n! / ( n - a )! X a!
So on calculating the combination we get,
= 4 X 3 + 3 X 5 + 4 X 5
= 12 + 15 + 20
= 47
Therefore, the number of combinations of 2 health care providers of different types possible are 47.
Answer:
6x/4-24=x-2
6x/4-24/1=x-2
(6x/4)1-(24/1)4=x-2
6x/4-96/4=x-2
(6x-96)/4=(x-2)/1
Then cross multiply to get this;
(6x-96)1=(x-2)4
6x-96=4x-8
6x-96+96=4x-8+96
6x=4x+88
6x-4x=4x-4x+88
2x=88
Divide both sides by 2
2x÷2=88÷2
x=44
Thank you.
BY GERALD GREAT.