Answer:
The weight of the landing craft in the vicinity of Callisto's surface is 3480 N.
Explanation:
The engine of the craft provides an upward thrust of 
so that the space craft descends at a constant speed.
This implies that the net force on the space craft is zero.
The upward thrust will be equal to the downward gravitational pull by Callisto.
So the weight of the craft near the vicinity will be 3480 N.
Some call it "air resistance", and others just call it "drag".
The independent variable in this problem would be the different types of shower cleaner. The dependent variable would be the shower tiles.
Answer:
<em>There will be an increase in potential difference.</em>
Explanation:
As we know that the potential difference depends upon the capacitance.
ΔV = Q/C
When battery is disconnected the charge remains constant on the plates but the capacitance decreases. As the capacitance has an inverse relation with the potential difference, there will be an increase in it.
In addition to that the potential difference can also be defined as the product of field and distance between the plates. As the charge is constant so the field is constant. Upon increasing the separation between the plates the potential difference will also increased.
Answer:
The water is flowing at the rate of 28.04 m/s.
Explanation:
Given;
Height of sea water, z₁ = 10.5 m
gauge pressure, 
= 2.95 atm
Atmospheric pressure, 
= 101325 Pa
To determine the speed of the water, apply Bernoulli's equation;
where;
P₁ = 
P₂ =
v₁ = 0
z₂ = 0
Substitute in these values and the Bernoulli's equation will reduce to;
where;
is the density of seawater = 1030 kg/m³
Therefore, the water is flowing at the rate of 28.04 m/s.
