Answer:
Induced emf in the coil,
Explanation:
Given that.
Number of turns in the coil, N = 200
Side of square, d = 18 cm = 0.18 m
The field changes linearly from 0 to 0.50 T in 0.80 s.
To find,
The magnitude of the induced emf in the coil while the field is changing.
Solution,
We know that due to change in the magnetic field, an emf gets induced in the coil. The formula of induced emf is given by :
= magnetic flux
A is the ares of square
So, the induced emf in the coil is 4.05 volts. Hence, this is the required solution.
Answer:
91.3 kg
Explanation:
weight = m*g
m: mass
g: gravity = 9.8 or 10 (depends on what your instructor tells you to use)
mass = w/g
895/9.8 = 91.3 KG
Explanation:
The given data is as follows.
Fluid is water so, density 
Weight flow rate = 500 lbf/s = 2224.11 N/sec
Cross-sectional area (A) = 
= 0.05184 
Hence, weight flow rate will be given as follows.
w = 
2224.11 N/sec = 
V =
m/s
= 4.373 m/s
Thus, we can conclude that average velocity in the given case is 4.373 m/s.