For a function, each input(x) can only have ONE output (y). Is this a function?
1 answer:
You might be interested in
Using limits, it is found that the end behavior of the function is given as follows:
As x → -∞, f(x) → 4; as x → ∞, f(x) → 4.
<h3>How to find the end behavior of a function f(x)?</h3>The end behavior of a function f(x) is given by the limit of f(x) as x goes to infinity.
In this problem, the function is:
Considering that x goes to infinity, for the limits, we consider only the terms with the highest exponents in the numerator and denominator, hence:
.
.
Hence the correct statement is:
As x → -∞, f(x) → 4; as x → ∞, f(x) → 4.
More can be learned about limits and end behavior at brainly.com/question/27950332
#SPJ1
Answer (Please vote me Brainliest if this helps!):
The answer is D
Step-by-step explanation:
Lets start off with the square roots:
= 4
=
= 4.24264...
Mixed fraction:
= 4.667
Therefore the answer is D.
Answer:
The correct option is;
No, the distance from (0, 0) to (2, √6) is not 3 units
Step-by-step explanation:
The given parameters of the question are as follows;
Circle center (h, k) = (0, 0)
Point on the circle (x, y) = (3, 0)
We are required to verify whether point (2, √6) lie on the circle
We note that the radius of the circle is given by the equation of the circle as follows;
Distance² = (x - h)² + (y - k)² = r² which gives;
(3 - 0)² + (0 - 0)² = 3²
Hence r² = 3² and r = 3 units
We check the distance of the point (2, √6) from the center of the circle (0, 0) as follows;
Therefore;
(2 - 0)² + (√6 - 0)² = 2² + √6² = 4 + 6 = 10 = √10²
Which gives the distance of the point (2, √6) from the center of the circle (0, 0) = √10
Hence the distance from the circle center (0, 0) to (2, √6) is not √10 which s more than 3 units hence the point (2, √6), does not lie on the circle.