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Lera25 [3.4K]
3 years ago
9

((Helppp))if there are two equal forces being applied to an object of those two forces are in opposite directions what is it the

resultant scenario?
the forces are differential and cancel each other out

the forces are addictive and combined together to make a stronger force

it depends on which force is bigger the resultant force it will move in the direction of the largest force

none of the above​
Physics
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

my answer personally is A

Explanation:

because their in opposite directions

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Which of the following must be transformed into electrical energy when biomass is used as an energy resource?
dangina [55]
It’s chemical energy





Your welcome :)
3 0
4 years ago
The acceleration of gravity at the surface of Moon is 1.6 m/s2 . A 5.0 kg stone thrown upward on Moon reaches a height of 20 m.
kramer

Answer:

(a) 8 m/s

(b) 5 s

Explanation:

(a)

Using,

V² = U²+2gh ......................... Equation 1

Where V = final velocity, U = Initial velocity, g = acceleration due to gravity on the surface of the moon, h = height reached.

Given: V = 0 m/s ( At it's maximum height), g = -1.6 m/s² ( as its moves against gravity), h = 20 m.

Substitute into equation 1

0 = U²+[2×20×(-1.6)]

-U² = - 64

U² = 64

U = √64

U = 8 m/s.

(b)

V = U +gt.................... Equation 2

Where t = time to reach the maximum height.

Given: V = 0 m/s ( At the maximum height), g = -1.6 m/s² ( Moving against gravity), U = 8 m/s.

Substitute into equation 2

0 = 8+(-1.6t)

-8 = -1.6t

-1.6t = -8

t = -8/-1.6

t = 5 s.

5 0
3 years ago
A person exerts a horizontal force of 190 n in the test apparatus shown in the figure. Find the horizontal force that his flexor
DochEvi [55]

Answer:

Check explanation.

Explanation:

From the question, we know that The person exerted 190N, force on the flexor is unknown. Since, we don't have access to our diagram, we have to make one or two assumption; (1) that ba= 0.3 m, ac= 0.05.

Therefore, the horizontal force that his flexor muscle exerts on his forearm,F(flexor) = (190N) × (0.3m) / 0.05m.

The horizontal force that his flexor muscle exerts on his forearm,F(flexor) = 57 Nm/ 0.05 m.

The horizontal force that his flexor muscle exerts on his forearm,F(flexor) = 1140N.

5 0
3 years ago
What is the empirical formula of a compound that contains 27.0% s
eduard

Answer:

Empirical formula of the compound = SOCl₂

Explanation:

QUESTION:What is the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass?

The empirical formula of a compound is its simplest formula. It tells us

* The component element present in a molecule of the compound.

* The ratio  in which these elements are combined together, i.e mole ratio.

To calculate the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass. ( Relative atomic mass of S=32gmol⁻¹, 0=16gmol⁻¹, Cl=35.5gmol⁻¹)

                                           Sulphure S,  Oxygen O, Chlorine Cl

percentage by mass:            27.0%                  13.4%            59.6%

Step 1:

Divide by their relative

atomic mass:                     27.0/32.0      13.4/16.0         59.6/35.5    

⇒⇒⇒⇒⇒⇒⇒⇒⇒                  0.844            0.838            1.679

Step 2:

Divide by the

smallest mole ratio:       0.844/0.838   0.838/0.838  1.679/0.838

∴                                            1              :         1           :       2.

from the analysis above, the compound contains Sulphur, Oxygen and Chlorine in the ratio of 1:1:2.

∴ Empirical formula of the compound = SOCl₂

6 0
3 years ago
if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

Therefore, the mutual force between the two point charges is 319.64 N

4 0
3 years ago
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