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dedylja [7]
2 years ago
10

Two identical charges are located 1 m apart and feel a 1 N repulsive electric force. What is the charge of each particle.

Physics
1 answer:
Anit [1.1K]2 years ago
4 0

The charge on each particles which are 1 m apart and feeling a repulsive force of 1 N is 1.05×10¯⁵ C

<h3>Assumption </h3>

Let the charge on each particles be q

<h3>How to determine the charge </h3>
  • Final force (F) = 1 N
  • Distance apart (r) = 1 m
  • Electrical constant (K) = 9×10⁹ Nm²/C²
  • Charge on 1st particle (q₁) = q =?
  • Charge on 2nd particle (q₂) = q =?

The charge on each particle can be obtained by using the Coulomb's law equation as shown below:

F = Kq₁q₂ / r²

F = Kq² / r²

1 = (9×10⁹ × q²) / 1²

1 = 9×10⁹ × q²

Divide both side by 9×10⁹

q² = 1 / 9×10⁹

Take the square root of both side

q =  √(1 / 9×10⁹)

q = 1.05×10¯⁵ C

Learn more about Coulomb's law:

brainly.com/question/506926

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(a) The free-body diagram is shown in the attached figure.

Using the equations below, the initial accelerations of the two astronauts can be calculated:

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(b) Since the different between their mass is not much, we can deduce that:

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23 = 1/2 (8.445*10^-12)*t^2

t^2 = 5.447*10^12

t = 2333883.044 s = 27.013 days

(c) No, their accelerations will not be constant. It will increase because their radii would be decreasing.

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