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nlexa [21]
2 years ago
7

If a vector that is 3cm long represents 30 km/h, what velocity does a 5 cm long vector which is drawn using the same scale repre

sent?
A.50 km/h
B. 60 km/h
C. 100 km/h
Physics
1 answer:
poizon [28]2 years ago
5 0

Answer: A. 50 km/h

Explanation:

3 * 10 = 30

5 * 10 = 50

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Assuming that 1.0g of aspirin dissolves in 450 mL of water at 10o C, how much aspirin would be lost in the 1.4 mL of water added
ipn [44]

Answer:

amount of aspirin dissolved = 0.0031 g

so we can say that this is not affect % yield as amount of aspirin lost is very less

Explanation:

given data

mass of aspirin = 1 g

volume of water = 450 mL

solubility of aspirin temperature = 10° C

volume of water added = 1.4 mL

to find out

how much amount aspirin would be lost

solution

we know the solubility of aspirin is

solubility of aspirin = \frac{mass\ of\ aspirin}{volume\ of\ water}

solubility of aspirin =  \frac{1\ g}{450\ mL}  

solubility of aspirin = 2.2 × 10^{-3} g/mL

so

we can say

amount of aspirin dissolved =  solubility of aspirin × volume of water added

put here value

amount of aspirin dissolved = 2.2 × 10^{-3}  × 1.4

amount of aspirin dissolved =  3.1 × 10^{-3} g

amount of aspirin dissolved = 0.0031 g

so we can say that this is not affect % yield as amount of aspirin lost is very less

7 0
3 years ago
In the sum →A+→B=→C, vector →A has a magnitude of 12.0 m and is angled 40.0° counterclockwise from the +x direction, and vector
icang [17]

Answer:

Explanation: Ok, first caracterize the two vectors that we know.

A = ax + ay = (12*cos(40°)*i + 12*sin(40°)*j) m

now, see that C is angled 20° from -x, -x is angled 180° counterclockwise from +x, so C is angled 200° counterclockwise from +x

C = cx + cy = (15*cos(200°)*i + 15*sin(200°)*j) m

where i and j refers to the versors associated to te x axis and the y axis respectively.

in a sum of vectors, we must decompose in components, so: ax + bx  = cx and ay + by = cy. From this two equations we can obtain B.

bx= (15*cos(200°) - 12*cos(40°)) m = -23.288 m

by = (15*sin(200°) - 12*sin(40°)) m = -12.843 m

Now with te value of both components of B, we proceed to see his magnitude an angle relative to +x.

Lets call a to the angle between -x and B, from trigonometry we know that tg(a) = by/bx, that means a = arctg(12.843/23.288) = 28.8°

So the total angle will be 180° + 28.8° = 208.8°.

For the magnitude of B, lets call it B', we can use the angle that we just obtained.

bx = B'*cos(208.8°) so B' = (-23.288 m)/cos(208.8°) =  26.58 m.

So the magnitude of B is 26.58 m.

7 0
3 years ago
What is the magnitude of the angular momentum (in kgm2/s) of a 40 g golf ball flying through the air and spinning at 4300 rpm af
sladkih [1.3K]

Answer:

L=0.0045\ kg-m^2/s

Explanation:

Given that,

The mass of a golf ball, m = 40 g = 0.04 kg

Its angular velocity, \omega=4300\ rpm=450.29\ rad/s

The radius of the sphere is 2.5 cm or 0.025 m

We need to find the magnitude of the angular momentum of the ball. It is given by the formula as follows:

L=I\omega

Where I is moment of inertia

For sphere, I=\dfrac{2}{5}mr^2

L=\dfrac{2}{5}mr^2\omega\\\\L=\dfrac{2}{5}\times 0.04\times (0.025)^2\times 450.29\\\\L=0.0045\ kg-m^2/s

So, the magnitude of the angular momentum of the sphere is 0.0045\ kg-m^2/s.

4 0
2 years ago
List the 3 types of collisions that occur when your vehicle hits an object.
koban [17]

These collisions are: "a Vehicle Collision, a Human Collision, Internal Collision." A vehicle collision is a collision that involves two or more vehicles and is when the vehicles collide against each other creating a unbalanced force since how the force comes from opposite directions. A human collision would involve a vehicle and a human which would also be a unbalanced force but the human wouldn't have much affect of it's speed. A internal collision is when something happens inside the vehicle which decreases, or increases the vehicles speed.

Hope this helps!

7 0
3 years ago
PLEASEE HELP!!! LOTS OF POINTS AND BRAINLIEST!!!!!!!!
Dennis_Churaev [7]
A clock and a battery
3 0
2 years ago
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