Ecozone<span> is the broadest biogeographic division of the Earth's land surface, based on distributional patterns of terrestrial organisms.</span> A climatograph<span> is used to show the precipitation and the temperature of a region.
</span>
Explanation:
a) The process can be modeled as an adiabatic compression, because the pulses of pressurized air is governed into the tire and time frame is very small for any heat transfer through the tires. Hence, Q_net = 0.
The first law of thermodynamics states that the change in the internal energy is ∆U=Q-W= -W, since Q_net = 0 for adiabatic processes. Work is being done on the system by pumping action hence W_net is negative; therefore the change in the internal energy, ∆U, is positive. Since ∆U, is a function of initial and final temperatures the final final temperature must increase for ∆U to be positive.
b) The process can be modeled as an adiabatic expansion when a highly pressurized mixture of air and water is released into atmosphere from 20 atm to 1 atm. The time frame is very small for any heat transfer through the mixture. Hence, Q_net = 0.
The first law of thermodynamics states that the change in the internal energy is ∆U=Q-W= -W, since Q_net = 0 for adiabatic processes. Work is being done by the mixture on its surroundings due to change in pressure from high to low. The W_net is positive; therefore the change in the internal energy, ∆U, is negative. Since ∆U, is a function of initial and final temperatures the final final temperature must decrease for ∆U to be negative. The final temperatures drops below freezing point due to sudden adiabatic expansion of mixture leads to formation of snow.
Answer:
The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
Explanation:
Given;
coefficient of kinetic friction, μ = 0.84
speed of the automobile, u = 29.0 m/s
To determine the the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;
v² = u² + 2ax
where;
v is the final velocity
u is the initial velocity
a is the acceleration
x is the shortest distance
First we determine a;
From Newton's second law of motion
∑F = ma
F is the kinetic friction that opposes the motion of the car
-Fk = ma
but, -Fk = -μN
-μN = ma
-μmg = ma
-μg = a
- 0.8 x 9.8 = a
-7.84 m/s² = a
Now, substitute in the value of a in the equation above
v² = u² + 2ax
when the automobile stops, the final velocity, v = 0
0 = 29² + 2(-7.84)x
0 = 841 - 15.68x
15.68x = 841
x = 841 / 15.68
x = 53.64 m
Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
The answer is C: West to the East
The process of preparing a person to perform strenuous work and to recover from that work as quickly as possible is called training, I bet. Such w<span>arm up exercises as like stretching and other should lead person to the recovery. Hope it will help.</span>