Answer:
1.66 kg
Explanation:
Given that a 0.83-kg block is hung from and stretches a spring that is attached to the ceiling.
From Hook's law
F = Ke
But F = mg
Substitute mg for force in the Hook's law
Mg = ke
0.83 × 9.8 = ke
Make K the subject of formula
8.134 = Ke
K = 8.134 /e
Given that a second block is attached to the first one, and the amount that the spring stretches from its unstretched length triples.
That is
(0.83 + M) × 9.8 = K (3e)
Substitutes K into the above equation
(0.83 + M) × 9.8 = 8.134 / e (3e)
The e will cancel out
(0.83 + M) × 9.8 = 24.402
0.83 + M = 24.402/9.8
0.83 + M = 2.49
M = 2.49 - 0.83
M = 1.66 kg
Therefore, the mass of the second block is 1.66kg
When the balanced force is applied on the ball It will roll away from the force.
<u>Explanation:</u>
- A ball lies on the floor in rest. If the balanced force is applied to
the ball, the force will push away.
- The forces would include gravity and the forces of air particles entering the ball from almost all directions.
- And the ground is exercising the force and shifting away from the impact.
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Answer: e. P/2
Explanation:
For ideal gases, we have the relation:
P*V = n*R*T
where:
n = number of mols
R = Gas constant
T = temperature
V = volume
P = pressure.
We know that for sample A, we have n moles, a temperature T and a volume V, then the pressure of this sample will be:
Pa = (n*R*T)/V.
For sample B, we have:
n/2 moles, temperature T/2 and a volume V/2, then the pressure will be:
Pb = (n/2)*R*(T/2)*(2/V) = (n*R*T/V)*(2/4)
and:
(n*R*T/V) = Pa
Then we can replace it and we get:
Pb = (n*R*T/V)*(2/4) = Pa*(2/4) = Pa*(1/2) = Pa/2.
Then the correct option is e.
