All categories

3 years ago

Where do we get all of our simple and complex carbohydrates from

Chemistry

1 answer:

7nadin3 [17]3 years ago

7 0

Answer & explanation:

Carbohydrates (both simple and complex) are found in all plant foods, due to the fact that plants produce them during photosynthesis and use carbohydrates as their energy source.

Some examples of carbohydrate rich foods are corn, rice, potatoes and pasta as well. Honey and dairy foods also have carbohydrates.

Carbohydrates also have structural function, such as cellulose, which is the main component of plant cell walls, and chitin, which can be found in the atropod exoskeleton.

You might be interested in

Anna71 [15]

Answer:

This flexible ability is important because it allows the cell to survive in differing environments, such as when immersed in water over long periods of time.

4 0

3 years ago

A tank of oxygen has a volume of 1650 L. The temperature of the gas inside is 35?C. If there are 9750 moles of oxygen in the tan

Paul [167]

Answer:

2192.64 PSI.

Explanation:

From the general law of ideal gases:

PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the container in L (V = 1650 L).

n is the no. of moles of the gas in mol (n = 9750 mol).

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature of the gas in (T = 35°C + 273 = 308 K).

∴ P = nRT/V = (9750 mol)(0.082 L.atm/mol.K)(308 K)/(1650 L) = 149.2 atm.

To convert from atm to PSI:

1 atm = 14.696 PSI.

∴ P = 149.2 atm x (14.696 PSI/1.0 atm) = 2192.64 PSI.

4 0

3 years ago

Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h

Gwar [14]

Answer:

0.264 g of $CO_2$ can be formed from 288 mg of $O_2$

Explanation:

The balanced chemical equation is

$2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O$

The conversions are

Mass in mg $O_2$ is converted to mass in g $O_2$

Mass in g $O_2$ is converted to moles $O_2$ by dividing with molar mass

Moles $O_2$ is converted to moles $CO_2$ by using the mole ratio of $O_2:CO_2$ is 9 : 6

Moles $CO_2$ is converted to mass $CO_2$ by multiplying with molar mass $CO_2$

mass in mg $O_2$ > mass in g $O_2$ >moles $O_2$ > moles $CO_2$ > mass $CO_2$

$288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}$

=0.264g (Answer)

7 0

4 years ago

Identify Which two types of subatomic particles are located in the nucleus?

Ivan

Answer:

protons and neutrons

Explanation:

4 0

3 years ago

What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric

Gre4nikov [31]

The mass of NaCl formed is 8.307 grams

calculation

step 1: write the equation for reaction

Na₂CO₃ + 2HCl → 2 NaCl +CO₂ +H₂O

Step 2: find the moles of Na₂CO₃

moles = mass/molar mass

The molar mass of Na₂CO₃ is = (23 x2) + 12 + ( 16 x3) = 106 g/mol

moles = 7.5 g/106 g/mol =0.071 moles

Step 3: use the mole ratio to determine the mole of NaCl

Na₂CO₃:NaCl is 1:2 therefore the moles of NaCl =0.07 x2 =0.142 moles

Step 4: calculate mass of NaCl

mass= moles x molar mass

the molar mass of NaCl= 23 +35.5 =58.5 g/mol

mass = 0.142 moles x 58.5 g/mol =8.307 grams

8 0

3 years ago

Read 2 more answers