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Sergio039 [100]
3 years ago
15

Timbre describes the sound’s _____.

Chemistry
2 answers:
myrzilka [38]3 years ago
7 0
I would say buzzy, brassy, and, harsh
Hope this can be of use!
sergeinik [125]3 years ago
5 0

Answer:

Terms we might use to describe timbre: bright, dark, brassy, reedy, harsh, noisy, thin, buzzy, pure, raspy, shrill, mellow, strained. I prefer to avoid describing timbre in emotional terms (excited, angry, happy, sad, etc.); that is not the sound quality, it is its effect or interpretation

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B. .175


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stepan [7]

I’m assuming in this scenario that 2.5 mols of Fe2O3 is reacting with excess reactant. Based on the balanced equation, you can see that there’s a 1:2 ratio between Fe2O3 and Fe. This means that to find the mols of Fe formed, you need to multiply the mols of Fe2O3 by 2.
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Five the IUPAC names for the following
White raven [17]

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4 0
4 years ago
Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

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The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
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