Answer:
16,17 and 18
Step-by-step explanation:
In statistics mode of a set of entries is the entry which is repeated maximum. There can be more than one mode in a set of entries. These are called mode,
Bimode ( two mode ) , trimode ( three mode ) and Multimode ( four or more ) .
Hence here our set of entries is,
20,17,16,17,18,16,18,19
arranging them in ascending order
16,16,17,17,18,18,19,20
hence in this case we see that 16,17and 18 all are getting repeated for two times, the maximum.
Hence we have a trimode here
16,17,18
3 x 36= 108/4 = 27
27 is the answer
Answer:
a = -12
b = 3
Step-by-step explanation:
second term = a + 6b
to find the 5th term, notice the pattern (since this is a linear equation, each term increases by the same amount) and each term increases by 4b: 2b -> 6b -> 10b.
therefore, the 4th term would be a+14b and the 5th would be a+18b
so a + 6b = 8
and a + 18b = 44
u now have two simultaneous equations, which can be solved through substitution or elimination. I'm gonna use elimination because it's quicker in this case:
steps: (since the a would cancel out by subtracting, subtract then solve for b. divide by -12 on both sides to isolate the b)
now that u know the value of b, substitute it into an equation to solve for a:
a + 6b = 8
a + 6(3) = 8
a + 24 = 8
a = 8 - 24
a = -16
hope this helps!
Answer:
The area under the normal curve from the mean to 118.8. is 0.47
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Find the area under the normal curve from the mean to 118.8.
This is the pvalue of Z when X = 118.8 subtracted by the pvalue of Z when X = 100.
X = 118.8
has a pvalue of 0.97
X = 100
has a pvalue of 0.5
0.97 - 0.5 = 0.47
The area under the normal curve from the mean to 118.8. is 0.47
Its what the other guy said he is right