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3 years ago

A car goes North a distance of 120 kilometers during a time period of 3.0 hours. What is the average

Physics

1 answer:

DIA [1.3K]3 years ago

8 0

Answer:

the average speed of the car during this time interval is 40 m/s i thinkk..

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A joule is an amount of energy, and a watt is a rate of using energy, defined as 1 W = 1 J / s. How many joules of energy are re

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How many joules of energy are required to run a 100 W light bulb for one day?

A100 joulesB100W × 24hr joulesC100W × 24hr × 60min∕hr joulesD100W × 24hr × 60min∕hr × 60s∕min joules

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3 years ago

Which of the following tools measures weight? A balance A scale A cyclometer A graduated cylinder

Kazeer [188]

I'm pretty sure its a scale.

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3 years ago

How do charges act on insulators and conductors?

umka2103 [35]

Answer:

An insulator holds charge within its atomic structure. Objects with like charges repel each other, while those with unlike charges attract each other. A conducting object is said to be grounded if it is connected to the Earth through a conductor.

Explanation:

Source:https://courses.lumenlearning.com/physics/chapter/18-2-conductors-and-insulators/

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3 years ago

Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act.One acrobat has a mass of 60

earnstyle [38]

Answer:

1.36m/s

Explanation:

We are given that

Mass of one acrobat, $m_1=60 kg$

Mass of another acrobat, $m_2=50 kg$

$v_2=-3 m/s$

$v_1=5 m/s$

We have to find their velocity immediately after they grab onto each other.

The collision between two acrobat is inelastic

According to law of conservation of momentum

$m_1v_1+m_2v_2=(m_1+m_2)V$

Substitute the values

$60\times 5+50(-3)=(60+50)V$

$300-150=110V$

$V=\frac{300-150}{110}=1.36m/s$

4 0

3 years ago

An automobile of mass 1300 kg has an initial velocity of 7.20 m/s toward the north and a final velocity of 6.50 m/s toward the w

Svetradugi [14.3K]

Answer

given,

mass of the automobile = 1300 Kg

initial speed of the automobile in north direction= 7.20 j m/s

final speed of the automobile in west direction = -6.50 i m/s

now,

change in momentum

$\Delta P = m (v_f - v_i)$

$\Delta P = 1300\times (-6.50 \hat{i} - 7.20 \hat{j})$

$\Delta P = 1300\times \sqrt{(-6.50)^2 + (-7.20)^2}$

$\Delta P = 1300\times 9.7$

$\Delta P = 12610\ kg.m/s$

now, direction calculation

$\theta = tan^{-1}(\dfrac{7.2}{6.5})$

$\theta = tan^{-1}(1.1076)$

$\theta = 47.92^0$

direction of the car is 48° in south west direction.

3 0

3 years ago