Answer:
768 bugs
Step-by-step explanation:
You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.
f(x)=6*2^(x/5)
Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.
By plugging in 35, you get 6*2^7, which is 768.
-6 x 2 + 6 x 200. Since you want to find out 6 multiplied by 198 the easiest way (for me) would be to round it and then substract 12 since 200-198 is equal to 2 and 6 x 2 is equal to 12
Answer:
the first five terms are
a1 = 6
a2 = 24
a3 = 60
a4 = 120
a5 = 210
Step-by-step explanation:
the experission used to find the five terms is
an = n3+ 3n2+ 2n
