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OleMash [197]
3 years ago
14

Determine the intercepts of the line. y + 5 = 2(x + 1) y-intercept: T-intercept:

Mathematics
1 answer:
den301095 [7]3 years ago
7 0

Answer:

3 5 minus 2 equal 3 plus 1 equals 4

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In studies for a​ medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.
timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

p = 0.03

q = 1 - 0.03 = 0.97

The mean is

\mu  = np

\mu = 643 \times 0.03 = 19.29

The standard deviation is

\sigma =  \sqrt{npq}

\sigma =  \sqrt{643 \times 0.03 \times 0.97}

\sigma =4.33

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \:  \frac{24.5 - 19.29}{4.33} ) \\  = P( 0.97\: < \: z \: < \:  1.20) \\  = 0.051

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

P(X \: < \: 24.5) = P(z \: < \:  \frac{24.5 - 19.29}{4.33} )  \\ =   P(z \: < \: 1.20)  \\  = 0.8849

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

P(X \: > \: 10.5) = P(z \: > \:  \frac{10.5 - 19.29}{4.33} )  \\ = P(z \: > \:  - 2.03)

= 0.9788

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

P(23.5  \:  <  \: X \:  <  \: 28.5) = P( \frac{23.5 - 19.29}{4.33}   \:  <  \: z \:  <  \:  \frac{28.5 - 19.29}{4.33} ) \\  = P( 0.97\:  <  \: z \:  <  \: 2.13) \\  = 0.1494

3 0
3 years ago
A cell phone plan costs $39 a month. The plan includes 2 gigabytes (GB) of free data and
DerKrebs [107]

a) C(0.5) = 39,  C(2)  =  39,  C(4)  =  69

b) Answers in part (a) represents the values of C at x = x₀

c) C(x) is continuous at x = 2

C (x) = 39 for 0 ⩽ x ⩽ 2

Since x = 0.5 is in the range 0 ⩽ x ⩽ 2:

C(0.5)  =  39

Since x = 2 is in the range 0 ⩽ x ⩽ 2

C(2)  =  39

Since x = 4 is in the range x  >  2

C(4) = 39 + 15(x - 2)

C(4) = 39  +  15 (4 - 2)

C(4)  =  39  +  15(2)

C(4)  =  39  +  30

C(4)  =  69

b) The answers in part A represents C(x). That is, the values of C at x = x₀

c) Is C(x) continuous at x = 2

C(2)   =  39

\lim_{x \to 2} C(x) = 39

Since \lim_{x \to 2} C(x) = C(2), the function C(x) is continuous at x = 2

Learn more here: brainly.com/question/20710468

4 0
2 years ago
Jenny's lunch account has $10 in it. She buys lunch three days in a row and spends $2.50, $2, and $2.75. On the fourth day, she
defon
10-(2.5+2+2.75)+10-3 = 9.75
7 0
1 year ago
Read 2 more answers
NS SECTION ONE<br>In the number 416.98, which digit has the greatest value ​
Aneli [31]

the 4 because it's in the hundred place value

I THINK THAT"S HOW YOU DO IT, BUT YOU KNOW JUST TRYING TO HELP YOU :)

5 0
3 years ago
Which is the slope of a line that is parallel to the line represented by the equation x-y=8
pychu [463]

Answer:

slope of parral line is same as slope of line its 1

5 0
2 years ago
Read 2 more answers
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