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3 years ago

Why does the world rotate and never makes us feel it move?

2 answers:

6 0

The earth moves too slow for us to feel it. If the earth moved fast time would move faster, meaning we would move faster. We have adapted to our current living situation over millions of years. We have been used to it our entire lives.

jekas [21]3 years ago

3 0

-- The Earth is rotating HALF as fast as the hour hand on a clock ... one full rotation in 24 hours. Too slow to feel.

-- The Earth takes about 4 minutes to rotate ONE DEGREE (out of 360). Too slow to feel.

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Since sinusoidal waves are cyclical, a particular phase difference between two waves is identical to that phase difference plus

r-ruslan [8.4K]

Answer:

nπ + π/2 for any integer n

Explanation:

Since destructive interference occurs every odd multiple of half wavelength, that is π/2, 3π/2, 5π/2 where the interference is half wavelength and in general, (n + 1/2)π where n is an integer. So, nπ + π/2 for any integer n

4 0

3 years ago

A student on an amusement park ride moves in circular path with a radius of 3.5 m once every 4.5 s. What is the tangential veloc

nata0808 [166]

Answer:

the tangential velocity of the student is 4.89 m/s.

Explanation:

Given;

the radius of the circular path, r = 3.5 m

duration of the motion, t = 4.5 s

let the student's tangential velocity = v

The tangential velocity of the student is calculated as follows;

$v = \frac{2\pi r}{t} \\\\v = \frac{2 \pi \times 3.5}{4.5} \\\\v = 4.89 \ m/s$

Therefore, the tangential velocity of the student is 4.89 m/s.

6 0

3 years ago

If a rock has a weight of 30 N on Earth, would its weight be more or less if it was on Jupiter (gravity on Jupiter = 25 m/s2)?

goldenfox [79]

I’m sorry this is not going as planned

8 0

3 years ago

You throw a rock up into the air as hard as you can. It stays in the air a total of 6.0 s. What

vaieri [72.5K]

Answer:

Explanation:

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3 years ago

A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from

Ulleksa [173]

Answer:

$1270.64\ \text{J}$

Explanation:

m = Mass of object = $\dfrac{mg}{g}$

mg = Weight of object = 20 N

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

v = Final velocity = 15 m/s

u = Initial velocity = 0

d = Distance moved by the object = 150 m

$\theta$ = Angle of slope = $30^{\circ}$

f = Force of friction

fd = Work done against friction

The force balance of the system is

$\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}$

The work done against friction is $1270.64\ \text{J}$ .

8 0

3 years ago