Write the equation of the line that passes through the points (8, 14) and (-2,-16) in slope-intercept form.

Mathematics

1 answer:

Schach [20]3 years ago

7 0

Answer:

y = 3x - 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (8, 14) and (x₂, y₂ ) = (- 2, - 16)

m = $\frac{-16-14}{-2-8}$ = $\frac{-30}{-10}$ = 3 , then

y = 3x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (8, 14 ) , then

14 = 24 + c ⇒ c = 14 - 24 = - 10

y = 3x - 10 ← equation of line

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Step-by-step explanation:

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$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

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