Question

Write the equation of the line that passes through the points (8, 14) and (-2,-16) in slope-intercept form.

Answer 1

Answer:

y = 3x - 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (8, 14) and (x₂, y₂ ) = (- 2, - 16)

m = $\frac{-16-14}{-2-8}$ = $\frac{-30}{-10}$ = 3 , then

y = 3x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (8, 14 ) , then

14 = 24 + c ⇒ c = 14 - 24 = - 10

y = 3x - 10 ← equation of line