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yarga [219]
3 years ago
11

What two types of tactical communication vary based on whether or not you speak?

Physics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

If you don't have autism/deaf/anything like that you should be able to speak

Explanation:

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A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu
Setler79 [48]
<h2>Given :</h2>

  • total charge = 9.0 mC = 0.009 C

Each electron has a charge of :

1.6 \times 10 {}^{ - 19} \:  C

For producing 1 Cuolomb charge we need :

  • \mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }

  • \dfrac{10 {}^{19} }{1.6}

  • \dfrac{10\times 10 {}^{19} }{16}

  • \dfrac{100 \times 10 {}^{18} }{16}

  • \mathrm{6.24 \times 10 {}^{18}  \:  \: electrons}

Now, for producing 0.009 C of charge, the number of electrons required is :

  • 0.009 \times 6.24 \times  {10}^{18}

  • 0.05616 \times 10 {}^{18}

  • \mathrm{5.616 \times 10 {}^{16}  \:  \: electons}

_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

\mathrm{5.616 \times 10 {}^{16} \:  \: electrons}

Number of electrons passing through it in 1 Second is :

  • \dfrac{5.616 \times  {10}^{16} }{3.6}

  • \mathrm{1.56 \times 10 {}^{16}  \:  \: electrons}

Now, in 10 seconds the number of electrons passing through it is :

  • 10 \times  \mathrm{1.56 \times 10 {}^{16}  \:  \: }

  • \mathrm{1.56 \times 10 {}^{17}  \:  \: electrons}

_____________________________

\mathrm{ \#TeeNForeveR}

6 0
3 years ago
Nick is so excited to Trick-or-Treat, he RUNS down the street to the house that has the BIG candy bars! He ran 203 meters. It to
aleksandr82 [10.1K]
對不起,我沒有看到照片,我看到的都是黑色的東西。對不起。
6 0
3 years ago
Consider a situation in which you are moving two point charges such that the potential energy between them decreases. (NOTE: ign
Oxana [17]

Answer: Option A

Explanation:

The potential energy decreases in the case when the charges are opposite and they attract each other.

In this case there is no external energy required in order to put the charges together.

This is so because the charges are opposite and they will attract each other. Yes, the only condition should be that the charges should be alike.

Example: a negative charge and a positive charge.

5 0
3 years ago
Which objects will likely have the greatest gravitational force between them?
Mariulka [41]

Answer:

d. Two soccer balls that are touching each other

Explanation:

Let m_1 be the mass of a tennis ball, m_2 is the mass of a soccer ball.

As the mass of a soccer ball is more than the mass of a tennis ball, so

m_2 > m_1

Let d_1 be the distance between the centers of both the balls near each other and d_2 be the distance between the centers of both the balls touching each other.

So, d_2 > d_1

The gravitational force, F, between the two objects having masses M and m and separated by distance d is

F=\frac{GMm}{d^2}

Where G is the universal gravitational constant.

As, the gravitational force is directly proportional to the product of both the masses and inversely proportional to the square of the distance between them,  so selecting the larger mass (m_2, soccer ball) separated by a lesser distance (d_2, touching) to get more gravitational force.

Therefore, there will be a larger gravitational force between them when two soccer balls touching each other.

Hence, option (d) is correct.

3 0
4 years ago
A barbellbell is loaded with two 20 kg plates on its right side and two 20kg plates on its left side. The barbell is 2.2m long,
Aleks [24]

Answer:

<h2>Center of gravity of the system of all masses is 105 cm from the left end of the rod</h2>

Explanation:

Let the position of Left end of the rod is our reference

So here we will have

m_1 = 20 kg

x_1 = 20 cm

m_2 = 20 kg

x_2 = 30 cm

m_3 = 20 kg

x_3 = 110 cm

m_4 = 20 kg

x_4 = (220 - 40) = 180 cm

m_5 = 20 kg

x_5 = (220 - 35) = 185 cm

so we will have

x_{cm} = \frac{m_1x_1 + m_2x_2 + m_3x_3 + m_4x_4 + m_5x_5}{m_1 + m_2 + m_3 + m_4 + m_5}

x_{cm} = \frac{20(20 + 30 + 110 + 180 + 185)}{20 + 20 + 20 + 20 + 20}

x_{cm} = 105 cm

7 0
4 years ago
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