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uranmaximum [27]
2 years ago
13

SOMEBODY HELP ME PLEASE​

Mathematics
1 answer:
olga2289 [7]2 years ago
6 0

Answer:

the answer is 2x-2

hopes this helpas

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How do I find simple interest rate
-BARSIC- [3]
For interest rate question    I=p times r times t
17=500 times r times 2
17 divide 1000
then multiply 100 to get percentage
1.7%
8 0
3 years ago
Combine like terms to find the equivalent expression to 6(5/8u+1)-6(-7/4u-5)
IgorLugansk [536]

Answer:

B

Step-by-step explanation:

Distribute 6 to 5/8u and 1 and you get 15/4u + 6. Distribute -6 to -7/4u and -5 and you get 21/2u and 30. The equation will be 15/4u + 6 + 21/2u + 30 and then combine like terms to get 57/4u + 36.

6 0
3 years ago
Use the figure to the right to find the value of PT. T is the midpoint of PQ.
o-na [289]

Answer:

PT = 17

Step-by-step explanation:

Since T is the midpoint of PQ, then

PT = TQ , substitute values

4x + 5 = 8x - 7 ( subtract 4x from both sides )

5 = 4x - 7 ( add 7 to both sides )

12 = 4x ( divide both sides by 4 )

3 = x

Thus

PT = 4x + 5 = 4(3) + 5 = 12 + 5 = 17

4 0
3 years ago
Read 2 more answers
Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
3 years ago
What is the midpoint of a segment (-2,-7) and (7,4)
Rasek [7]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-7})\qquad
(\stackrel{x_2}{7}~,~\stackrel{y_2}{4})
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{7-2}{2}~~,~~\cfrac{4-7}{2} \right)\implies \left(\cfrac{5}{2}~,~\cfrac{-3}{2} \right)\implies \left( 2\frac{1}{2}~,~-1\frac{1}{2} \right)

5 0
3 years ago
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