(A)Nuclear change..............
Answer:
1528.3L
Explanation:
To solve this problem we should know this formula:
V₁ / T₁ = V₂ / T₂
We must convert the values of T° to Absolute T° (T° in K)
21°C + 273 = 294K
70°C + 273 = 343K
Now we can replace the data
1310L / 294K = V₂ / 343K
V₂ = (1310L / 294K) . 343K → 1528.3L
If the pressure keeps on constant, volume is modified directly proportional to absolute temperature. As T° has increased, the volume increased too
Answer:
the second one looks like it so I picked the second one
Answer:
I think it will carbon hope it helps
Solution :
a). 
This compound is known as sulfur trioxide.
The molecular shape of sulfur trioxide is trigonal planer.
And the bond angle is 120°.
b). 
This compound is known as Nitrous oxide. Here, nitrogen is in the center. There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.
It is linear in shape.
The bond angle between them is 180°.
c). 
This compound is known as the Dichloromethane.
The molecular shape of the compound is tetrahedral.
The bond angles is 120°