Question

How many moles of HNO3 are present in 697 grams of HNO3?

Answer 1

Answer:

Explanation:

given mass = 697 g

molar mass = mass of H × mass of N × 3 × mass of O

= 1 × 14 × 3 × 16 = 672 g

no. of moles = given mass / molar mass = 697 / 672 = 1.03 moles

Hope this helps

plz mark as brainliest!!!!!!