The coefficient for hydrogen in the balanced equation of solid molybdenum(iV) oxide with gaseous hydrogen is 2
Explanation
Coefficient is defined to as a number in front of a chemical formula in a balanced chemical equation.
The reaction of molybdenum (iv) oxide with gaseous hydrogen is as below,
MoO2 + 2 H2→ Mo +2 H2O
From balanced equation above the coefficient for H2 is 2 since the number in front of H2 is 2
C) Fluorine is the most reactive among halogens
Answer:
B
Explanation:
First of all it is important to know that a half filled orbital is particularly stable. In phosphorus all the electrons occur singly in the 3p sublevel minimizing inter electronic repulsion hence it is more difficult to remove an electron from this energetically stable arrangement. In sulphur, electrons are paired in one of the 3p orbitals thereby lowering the energy of that level due to instability caused by interelectronic repulsion between two electrons in the same orbital.
Answer:
D. One soluble and one insoluble salts are formed
Explanation:
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
Mass of compound = 16.75 g
Mass of Oxygen = 14.02 g
Mass of Hydrogen = 2.73 g
Percentage composition = Mass of element / Mass of compound 100%
Percentage composition of Oxygen = 14.02 g / 16.75 g * 100%
Percentage composition of Oxygen = 0.837 * 100 = 83.7%
Percentage composition of Hydrogen = 2.73 g / 16.75 g * 100%
Percentage composition of Hydrogen = 0.163 * 100 = 16.3%
The correct option is;
83.7% oxygen, 16.3% hydrogen