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Nataly_w [17]
2 years ago
12

An element forms an oxide, E₂O₃, and a fluoride, EF₃.(b) How does the group to which E belongs affect the properties of the oxid

e and the fluoride?
Chemistry
1 answer:
xz_007 [3.2K]2 years ago
6 0

Of all the elements, fluorine is the most electronegative and reactive. Fluorine is a diatomic, pale yellow, extremely corrosive, combustible gas with a strong smell. The lightest halogen is it. It produces oxygen and the incredibly corrosive hydrofluoric acid when it combines strongly with water.

<h3>The properties of the oxide and the fluoride?</h3>
  • 1. A mixture of oxygen fluorides with an atomic ratio OF in the range of 1.1-2.04 is generated when fluorine and oxygen mixes are easily circulated through a silent electric discharge.
  • Depending on where you reside in the UK, fluoride is a naturally occurring mineral that is present in water in variable concentrations. It is added to many types of toothpaste and, in some locations, the water supply through a procedure known as fluoridation because it can aid in the prevention of tooth decay.
  • Fluoride stops tooth decay by strengthening the enamel's resistance to acid attack. They also quicken the process of good minerals accumulating in the enamel, further delaying the onset of deterioration. Studies also suggest that fluoride may occasionally be able to stop tooth decay that has already begun.

To know more about Fluoride please click here : brainly.com/question/10929330

#SPJ4

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What is the freezing point in °C) of a 0.195 m
Elina [12.6K]

Answer:

T_S=-1.09\°C

Explanation:

Hello!

In this case, since the freezing point depression for a solution is computed via:

(T_S-T_W)=-imK_f

Whereas TW is the freezing temperature of water, TS that of the solution, i the van't Hoff's factor (3 for K2S as it ionizes properly), m the molality of the solution and Kf the freezing point constant of water. Thus, we plug in to obtain:

(T_S-0\°C)=-3*0.195m*1.86\frac{\°C}{m}\\\\T_S=-1.09\°C

Best regards!

4 0
3 years ago
Read 2 more answers
Find the number of Li atoms in 1.50 mole of Li
ale4655 [162]
The molar mass of Li->7g/mol
If 1mol of Li is 7g/mol
1.50mol of Li would be 10.5g/mol
7 0
3 years ago
PLS I NEED HELP give me examples of an atom
Ugo [173]

Answer:

Neon (Ne)

Hydrogen (H)

Argon (Ar)

Iron (Fe)

Calcium (Ca)

Deuterium, an isotope of hydrogen that has one proton and one neutron.

Plutonium (Pu)

F-, a fluorine anion.

Explanation:

I got u

4 0
3 years ago
A dark brown binary compound contains oxygen and a metal. It is 13.38% oxygen by mass. Heating it moderately drives off some of
Leto [7]

Answer:

a) Mass of O in compound A = 32.72 g

Mass of O in compound B =  21.26 g

Mass of O in compound C = 15.94 g

b) Compound A = MO2

Compound B = M3O4

Compound C = MO

c) M = Pb

Explanation:

Step 1: Data given

A binairy compound contains oxygen (O) and metal (M)

⇒ 13.38 % O

⇒ 100 - 13.38 = 86.62 % M

After heating we get another binairy compound

⇒ 9.334 % O

⇒ 100 - 9.334 = 90.666 % M

After heating we get another binairy compound

⇒ 7.168 % O

⇒ 100 - 7.168 = 92.832 % M

The first compound has an empirical formula of MO2

⇒ 1 mol M for 2 moles O

Step 2: Calculate amount of metal and oxygen in each

compound A:   M  = m1 *0.8662    O = m1 *0.1338

compound B:   M  = m2 *0.90666    O = m2 *0.09334

compound C:   M  = m3 *0.92832    O = m3 *0.07168

Step 3: Calculate mass of oxygen with 1.000 grams of M

Compound A: 1.000g * 0.1338 m1gO  / 0.8662m1gMetal = 0.1545

Compound B: 1.000g * 0.09334 m2gO  / 0.90666m2gMetal = 0.1029

Compound C: 1.000g * 0.07168 m3gO  / 0.92832m3gMetal = 0.07721

Step 4:

1 mol MO2 has 1 mol M and 2 moles O

m1 = (mol O * 16)/0.1338   m1 = 239.2 grams

1 mol M = 0.8632*239.2 = 206.48

0.90666m2 = 206.48  ⇒ m2 = 227.74 g

0.92832m3 = 206.48  ⇒ m3 = 222.42 g

Step 5: Calculate mass of O

Mass of O in compound A = 239.2 - 206.48 = 32.72 g

Mass of O in compound B = 227.74 - 206.48 = 21.26 g

Mass of O in compound C = 222.42- 206.48 = 15.94 g

Step 6: Calculate moles

Moles of O in compound A ≈ 2

⇒ MO2

Moles of O in compound B = 21.26 / 16 ≈ 1.33

⇒ M3O4

Moles of O compound C = 15.94 /16 ≈ 1 moles

⇒ MO

Step 7: Calculate molar mass

The mass of 1 mol metal is 206.48 grams  ⇒ molar mass ≈ 206.48 g/mol

The closest metal to this molar mass is lead (Pb)

6 0
3 years ago
An atom has an average atomic mass of about 63.5 amu. What is the chemical symbol for the atom? Consult the periodic table.
bearhunter [10]
An atom has an average atomic mass of about 63.5 amu. 
<span>
1 amu is equal to 1 gram per mole

so 63.5 amu is just equal to 63.5 grams per mole or 63.5 g/mol
the answer is Cu or copper.
</span>
4 0
4 years ago
Read 2 more answers
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