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taurus [48]
3 years ago
11

Which of the following will increase the number of collisions without changing the energy of reactant molecules?

Chemistry
1 answer:
natulia [17]3 years ago
6 0

Answer:increasing the concentration of reactants

Explanation:

Collision is the phenomenon in which the reactant molecules come to nearest closness,as a result the reactants are converted into products.

Now the number of effective collision is directly proportional to the number of reactants added..

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What is the basic SI unit of time
aniked [119]

Answer:

The base unit for time is the second the other SI units are: metre for length, kilogram for mass, ampere for electric current, kelvin for temperature, candela for luminous intensity, and mole for the amount of substance!

Explanation:

I hope i helped =)

5 0
3 years ago
Which option is an example of a physical property?
4vir4ik [10]
Physical property is C.Density
4 0
4 years ago
Read 2 more answers
If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
Helen [10]

This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0
3 years ago
what is the half life isotope if after 21 days you have 31.25 g remaining from a 250.0 g starting sample size?
alexgriva [62]

250 --> 125 --> 62.5 --> 31.25


each arrow equals one half life, so 3 half lives


14 days/ 3 half lives =


4.67 days = half life

3 0
3 years ago
Please help me with these two questions
ANEK [815]
What is the question?
8 0
3 years ago
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