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Naily [24]
3 years ago
10

In an open circuit like the picture

Physics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

what do i put as an answer it is not asking any Questions can you edit your question and put a bigger picture then i can help you and i will answer your Question better

Explanation:

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!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Korvikt [17]

Answer:

Second choice

Explanation:

I suppose ME is the same as POTENTIAL energy

ME = mgh =  70 * 10 * 12 = 8400j

  Half way down,   4200 j is converted to Kinetic Energy

       1/2 m v^2 = 4200

       1/2 (70)  v^2 = 4200       v = 10.95 m/s

  Just before impact ALL of the 8400 j is now KE
      1/2 (70)v^2 = 8400          v = 15.49 m/s

4 0
2 years ago
slader A baseball player slides to a stop on level ground. Using energy consideration, calculate the distance the 65 kg baseball
stich3 [128]

Answer:

2.6 m

Explanation:

From work energy theorem we deduce that

0.5mv^{2}=fd

The kinetic energy equals to the work dine against friction energy.

Where m represent mass, v is the velocity, f is the frictional force and d is unknown distance that the player slides.

Making d the subject of the formula then d=\frac {mv^{2}}{2f}

Then by substituting 450N for f, 65 kg for m and 6 m/s for v we obtain

d=\frac {65*6^{2}}{2*450}=2.6m

6 0
3 years ago
Give three examples that show the importance of gravity to humans
kow [346]
1-Without gravity you can't grow any plant or tree because dirt would fly away
2-We are using gravity for a lot of physics system too
3-All the water on Earth would have been flying in the space
4-There wouldn't be atmosphere.
3 0
3 years ago
Help!!!!!!!!!!!!!!!!!plz!!!!!!!!!!!!!!!!!!!!!
Zarrin [17]
Wrap wire around B the nails
4 0
3 years ago
Read 2 more answers
A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the rail
disa [49]

Answer

given,

mass of ice hockey player = 110 Kg

initial speed of the skate = 3 m/s

final speed of the skate = 0 m/s

distance of the center of mass, m = 30 cm = 0.3 m

a) Change in kinetic energy

    \Delta KE = \dfrac{1}{2}mv_f^2 - \dfrac{1}{2}mv_i^2

    \Delta KE = \dfrac{1}{2}m(0)^2 - \dfrac{1}{2}\times 110 \times 3^2

    \Delta KE = - 495\ J

b) Average force must he exerted on the railing

     using work energy theorem

      W = Δ KE

      F .d  = -495

      F x 0.3  = -495

      F = -1650 N

the average force exerted on the railing is equal to 1650 N.

7 0
3 years ago
Read 2 more answers
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