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2 years ago

In lewis structures, a solid line is used to represent...

Chemistry

1 answer:

sashaice [31]2 years ago

5 0

Answer:

in lewis structure, a solid line is usually used to represent a bond between the atoms

Explanation:

the dots that are shown around the atom represent the valence electrons on the outer shell

when there are multiple atoms, either a pair of dots circled (one dot from each atom) or a solid line is used to show the bonds between those atoms

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How can an experiment support or fail support a hypothesis

melomori [17]

If a hypothesis is stated and outcome of the experiment is what was predicted, then it supports the hypothesis. if the experiment does not support the hypothesis, then the outcome was not what was predicted.

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2 years ago

A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i

Damm [24]

The correct answer is A 0.75 atm

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3 years ago

Read 2 more answers

Which of the following is not a negative consequence of upward urban growth?

Anestetic [448]

Answer:

D. Waste management issues

Explanation:

Answer A: The five major types of pollution - water pollution, air pollution, land pollution, light pollution, noise pollution - have negative effects on the environment, on human health, and our planet as a whole.

Answer B: Urban Heat Island (UHI) is an urban area that is significantly warmer than its surrounding rural areas due to human activities. UHI decreases air quality.

Answer C: The increased use of surrounding land is the main cause of biodiversity loss.

Answer D: Any field of environmental management help people to solve pollution problems. So, D is the correct answer.

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Hope this answer can help you. Have a nice day!

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2 years ago

The concentration of reactant doesn't affect the activity

pashok25 [27]

Answer:

B.false because if the reactant concentration is disturbed the whole reaction will be affected.

Explanation:

6 0

2 years ago

What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i

UNO [17]

Answer:

$Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)$

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

$Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-$

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

$Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)$

The net equation is then:

$Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)$

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

$Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-$

Actual cathode half-equation:

$Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)$

Actual net reaction:

$Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)$

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3 years ago