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yanalaym [24]
3 years ago
13

2. Aqueous lead (II) nitrate reacts with aqueous potassium chloride and produces

Chemistry
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

302i83oeheiehdodnfifnf

Explanation:

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How many atoms are in 5 mole of water?<br> Steps
Vladimir79 [104]

Answer: 3.01 x 10^24 atoms

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of water = 6.02 x 10^23 atoms

5 moles of water = Z atoms

To get the value of Z, cross multiply

Z x 1 mole = (6.02 x 10^23 atoms x 5 moles)

Z•mole = 30.1 x 10^23 atoms•mole

Divide both sides by 1 mole

Z•mole/1 mole = 30.1 x 10^23 atoms•mole/ 1 mole

Z = 30.1 x 10^23 atoms

[Place the value of Z in standard form]

Z = 3.01 x 10^24 atoms

Thus, there are 3.01 x 10^24 atoms in 5 mole of water

3 0
3 years ago
Please solve this for 13 points
Anit [1.1K]

Answer:

sodium

Explanation:

everybody already known its sodium

6 0
3 years ago
A horse gallops along a racecourse at a speed of 40 km/h. It takes the horse 3 minutes to run the length of the track.
Natali [406]

To convert minutes to hours we divide the minutes by 60. So if we divide 3 by 60 we get 0.05 hours.

<h3>How to convert minutes into hour?</h3>

We know that in hour, there are 60 minutes so if we go from minutes to hours then we have to divide the number by 60 and when we go from hours to minutes we multiply with the same 60 number.

So we can conclude that to convert minutes to hours we divide the minutes by 60. So if we divide 3 by 60 we get 0.05 hours.

Learn more about hour here: brainly.com/question/291457

#SPJ1

7 0
2 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
3 years ago
You are on a flight to Los Angeles, California. As the plane gets ready to land, it flies out over a large body of water. You lo
sergey [27]

What ocean is next to California on google maps? That is your answer.

7 0
3 years ago
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